Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Counting

We invite all community contributors to share resources that are deemed to help students beat the GMAT. We've created individual threads to match the main topics, so please select the best fit for your content carefully.
Expert replies
by Arun6765 » Thu Mar 09, 2017 9:12 am
4.Amit has five friends: 3 girls and 2 boys. Amit’s wife also has 5 friends : 3 boys and 2
girls. In how many maximum number of different ways can they invite 2 boys and 2 girls such
that two of them are Amit’s friends and two are his wife’s? [spoiler](Ans:c)[/spoiler]
(a) 24
(b) 38
(c) 46
(d) 58
(e)68
Join the discussion
Source: — Helpful Resources |

Counting

by [email protected] » Thu Mar 09, 2017 9:19 am
Hi Arun6765,

In the future, you should make sure to post questions into the proper sub-Forums. For example, the PS Forum is here:

https://www.beatthegmat.com/problem-solving-f6.html

This specific type of prompt is relatively rare (you probably won't see it on Test Day). From a 'math standpoint', you can solve it by using the Combination Formula in a really specific way:

The question asks for the number of 'groups' that can be formed of 2 boys and 2 girls (with the added condition that 2 people come from Amit's friends and 2 come from his wife's friends). There are 3 ways that this can occur....

1) 2 boys from Amit; 2 girls from his wife
2) 2 girls from Amit; 2 boys from his wife
3) 1 boy and 1 girl from each

1st option = (2C2)(2C2) = (1)(1) = 1 option
2nd option = (3C2)(3C2) = (3)(3) = 9 options
3rd option = (3)(2)(3)(2) = 36 options

Total = 1+9+36 = 46

Final Answer: C

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by AlexBarret » Thu May 11, 2017 11:43 am
Arun6765 wrote:4.Amit has five friends: 3 girls and 2 boys. Amit’s wife also has 5 friends : 3 boys and 2
girls. In how many maximum number of different ways can they invite 2 boys and 2 girls such
that two of them are Amit’s friends and two are his wife’s? [spoiler](Ans:c)[/spoiler]
(a) 24
(b) 38
(c) 46
(d) 58
(e)68
Such an original quastion! Why do I have to think about maximum number of different ways to invite the friends? Is it so important?))
Join the discussion

by Matt@VeritasPrep » Wed Jul 05, 2017 12:05 am
AlexBarret wrote:
Arun6765 wrote:4.Amit has five friends: 3 girls and 2 boys. Amit’s wife also has 5 friends : 3 boys and 2
girls. In how many maximum number of different ways can they invite 2 boys and 2 girls such
that two of them are Amit’s friends and two are his wife’s? [spoiler](Ans:c)[/spoiler]
(a) 24
(b) 38
(c) 46
(d) 58
(e)68
Such an original quastion! Why do I have to think about maximum number of different ways to invite the friends? Is it so important?))
A quaint one too - who gets invited to anything any more? It seems like people just digitally announce events (or maybe I've been living in California too long ...)
Join the discussion

by Risfy1994 » Fri Dec 29, 2017 2:18 am
Hi there! To my mind, the right answer is c, but I am not sure at all. So which one is correct?
Join the discussion

Re: Counting

by Tony Mai » Fri Dec 11, 2020 4:24 am
Who has the answer to how many results yet. Can you share it with me?
Join the discussion

Re: Counting

by LeoGarben » Tue Jan 31, 2023 5:01 am
thanks for the post
Join the discussion