Hi,
Request help with the following question.Thanks..
Find the area enclosed between y=0,x=0 and 5x +7y=35
Coordinate Geometry - 1
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- vk_vinayak
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y=0 means X axis, and x=o means Y axis. So, it's a rt angled triangle.
From the equation of a line given we need to find out where that line intersexts X axis and Y axis.
Put x=o, and we get y=5
Put y=0 and we get x=7. So the points are (0,5) and (7,0) (the other verice of the triangle is (0,0)
That means base is 7 and height is 5.
Area = (1/2) * base * height = (1/2).7.5 = 35/2
Edit: Found a diagram for this equation: https://www.algebra.com/cgi-bin/plot-for ... %29&x=0003
From the equation of a line given we need to find out where that line intersexts X axis and Y axis.
Put x=o, and we get y=5
Put y=0 and we get x=7. So the points are (0,5) and (7,0) (the other verice of the triangle is (0,0)
That means base is 7 and height is 5.
Area = (1/2) * base * height = (1/2).7.5 = 35/2
Edit: Found a diagram for this equation: https://www.algebra.com/cgi-bin/plot-for ... %29&x=0003
- VK
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