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Coordinate G

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by vipulgoyal » Mon Jun 10, 2013 2:52 am
Y=a(x-b)^2+P. Can you tell if y has intersects with x axis?
1). a<0
2). P>0

what i understand in order to to intersect with x axis , the y intesept must be positive and slope should be negtive,
Experts please explain how the given line sastifying both conditions because ans is C
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by Jim@StratusPrep » Wed Jun 12, 2013 12:51 pm
This is a bit outside of the scope of the GMAT, but the negative 'a' coefficient means the parabola opens downward and the positive 'P' variable means the vertex has a positive y value. Thus, the parabola must cross the x-axis twice.
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by Atekihcan » Thu Jun 13, 2013 12:22 am
Jim@StratusPrep wrote:This is a bit outside of the scope of the GMAT, but the negative 'a' coefficient means the parabola opens downward and the positive 'P' variable means the vertex has a positive y value. Thus, the parabola must cross the x-axis twice.
If you think in terms of parabola, then yes this is beyond the scope of GMAT.
But this can very well be explained with basic concepts as I did here >> https://www.beatthegmat.com/coordinate-g ... tml#678269
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