Coordinate G

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vipulgoyal: Master | Next Rank: 500 Posts; Posts: 468; Joined: Mon Jul 25, 2011 10:20 pm; Thanked: 29 times; Followed by:4 members

Coordinate G

by vipulgoyal » Mon Jun 10, 2013 2:52 am

Y=a(x-b)^2+P. Can you tell if y has intersects with x axis?
1). a<0
2). P>0

what i understand in order to to intersect with x axis , the y intesept must be positive and slope should be negtive,
Experts please explain how the given line sastifying both conditions because ans is C

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Jim@StratusPrep: MBA Admissions Consultant; Posts: 2279; Joined: Fri Nov 11, 2011 7:51 am; Location: New York; Thanked: 660 times; Followed by:266 members; GMAT Score:770

by Jim@StratusPrep » Wed Jun 12, 2013 12:51 pm

This is a bit outside of the scope of the GMAT, but the negative 'a' coefficient means the parabola opens downward and the positive 'P' variable means the vertex has a positive y value. Thus, the parabola must cross the x-axis twice.

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Atekihcan: Master | Next Rank: 500 Posts; Posts: 149; Joined: Wed May 01, 2013 10:37 pm; Thanked: 54 times; Followed by:9 members

by Atekihcan » Thu Jun 13, 2013 12:22 am

Jim@StratusPrep wrote:This is a bit outside of the scope of the GMAT, but the negative 'a' coefficient means the parabola opens downward and the positive 'P' variable means the vertex has a positive y value. Thus, the parabola must cross the x-axis twice.

If you think in terms of parabola, then yes this is beyond the scope of GMAT.
But this can very well be explained with basic concepts as I did here >> https://www.beatthegmat.com/coordinate-g ... tml#678269

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