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Coordiante plane- How to arrive at the answer?

Expert replies
by Divya Ann Chacko » Tue Dec 17, 2013 8:20 pm
In the xy coordinate plane, is point R equidistant from points (-3,-3) and (1,-3)?
1) The x coordiante of point R is -1
2) Point R lies on the line y=-3
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Source: — Data Sufficiency |

Divya Ann Chacko wrote:In the xy coordinate plane, is point R equidistant from points (-3,-3) and (1,-3)?
1) The x coordiante of point R is -1
2) Point R lies on the line y=-3
Target question: Is point R equidistant from points (-3,-3) and (1,-3)?

This question is a great candidate for rephrasing the target question.
Aside: We have a free video with tips on rephrasing the target question: https://www.gmatprepnow.com/module/gmat- ... cy?id=1100

First sketch the two given points
Image

Notice that the point (-1, -3) is equidistant from the two given points. MORE IMPORTANTLY, every point on the line x = -1 is equidistant from the two given points.
Image

So, we can rephrase the target question . . .
Rephrased target question: Is point R on the line x = -1?

Statement 1: The x coordinate of point R is -1
If the x-coordinate is -1, then point R is definitely on the line x = -1
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: Point R lies on the line y= -3
This tells us nothing about whether or not point R is on the line x = -1?
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
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by Emi-Beth » Sun Jul 30, 2017 1:30 pm
I do not understand this answer. How can every point on the line x = -1 be equidistant from the given points? For example (-1,3) is not equidistant to the given points. Seems to me the only correct answer is (-1, -3). Please explain further why EVERY POINT ON THE LINE X=-1 IS EQUIDISTANT to the given points. I would understand this if we were plotting a straight line rather than points.
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by GMATGuruNY » Sun Jul 30, 2017 2:31 pm
Emi-Beth wrote:I do not understand this answer. How can every point on the line x = -1 be equidistant from the given points? For example (-1,3) is not equidistant to the given points. Seems to me the only correct answer is (-1, -3). Please explain further why EVERY POINT ON THE LINE X=-1 IS EQUIDISTANT to the given points. I would understand this if we were plotting a straight line rather than points.
Image

The SYMMETRY exhibited by the dashed blue line segments in the figure above illustrate why every point on x=-1 is equidistant from (-3, -3) and (1, -3).
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by Emi-Beth » Mon Jul 31, 2017 1:12 pm
Brilliant. Thank you. I understand now. my challenge was visualizing "equidistant" and your illustration shows this perfectly.
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