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Concert Attendance

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Concert Attendance

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Source: Kaplan

If Paul attends the concert, then Quinn or Ron will also attend. If Quinn attends, then Nat and Mark will also attend. If Mark attends, then Paul will attend. Ron and Mark cannot both attend.

If the above information is correct, which of the following must be true?

A. If Paul attends, then Nat attends
B. If Paul attends, then Nat or Mark attends
C. If Quinn attends, then Ron attends
D. If Ron attends, then Paul or Quinn attends
E. If Mark attends, then Quinn attends.

OA : E
Why it is E and not A?

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Master | Next Rank: 500 Posts Default Avatar
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longbyte75 wrote:
Source: Kaplan

If Paul attends the concert, then Quinn or Ron will also attend. If Quinn attends, then Nat and Mark will also attend. If Mark attends, then Paul will attend. Ron and Mark cannot both attend.

If the above information is correct, which of the following must be true?

A. If Paul attends, then Nat attends
B. If Paul attends, then Nat or Mark attends
C. If Quinn attends, then Ron attends
D. If Ron attends, then Paul or Quinn attends
E. If Mark attends, then Quinn attends.

OA : E
Why it is E and not A?
It took me little longer to solve this one.

P -> Q/R (Remember Q or R ...one of them) .....1
Q -> N & M (both will attend. If one of them doesn't attend, both will not go) .....2
M -> P .....3

So option A, p -> Q(not R because Ron cannot attend)
if Q -> None (because Mark cannot attend)

Option E
M attends ..meaning P will attend as per statement no. 3
if P attended then Q or P one of them will attend ..as per statement no. 1

HTH

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IMO E

A cannot be true always, if Paul attends then it is need not be necessary that Nat will attend. If Paul attends then Ron can attend and in this case Quinn may not attend and hence Nat will not attend.

E: If Mark attends then Paul attends, now in this case Quinn will attend and not Ron as Mark is also attending, so E is always true.
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I agree with abhi. E is the option that is always true.

This is a high level inference question. Use process of elimination to crack it.

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