B is correct.
60= only Cats+ only Dogs+ cats and dogs+ neither cats or dogs
We are given from St2 that cats and dogs= neither cats or dogs
Therefore 60= (only cats+cats and dogs) + (only dogs+ cats and dogs)
Hence 60=38 + Families that own dogs (this includes famiies that have only dogs and also own dogs and cats)
Hence ans is 22.
B wins.
Cats and dogs
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In the problem statement the following things are not known
1) How many of the families neither have a cat nor have a dog?
OR
2) How many families only have dog?
S-Neither = D + C -D and C
Statement 1:
Only Cat =28
Cat or Cat and Dog(D and C) = 38
So the above equation doesn't satisfy. Therefore Statement 1 is INSUFFICIENT
Statement 2:
S-X= D+C-X
60 = D+38
D = 22
Therefore, Statement 2 is SUFFICIENT
So B is the answer
1) How many of the families neither have a cat nor have a dog?
OR
2) How many families only have dog?
S-Neither = D + C -D and C
Statement 1:
Only Cat =28
Cat or Cat and Dog(D and C) = 38
So the above equation doesn't satisfy. Therefore Statement 1 is INSUFFICIENT
Statement 2:
S-X= D+C-X
60 = D+38
D = 22
Therefore, Statement 2 is SUFFICIENT
So B is the answer
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Using venn diagram, it can easily seen that (C) is the answer
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T-n = A+B - bothDanaJ wrote:Source: Veritas Prep
Of the 60 families in a certain neighborhood, 38 have a cat. How many of the families in this neighborhood have a dog?
(1) 28 of the families in this neighborhood have a cat but not a dog
(2) The number of families in the neighborhood who have a dog and a cat is the same as the number of families who have neither a cat nor a dog.
Experts: only Veritas Prep experts, please!
68- n= 38+B- both
From 2 we know n = both so
68 = 38 + B
so B = 30
Ans B
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Its not 68 but 60Ganesh hatwar wrote:T-n = A+B - bothDanaJ wrote:Source: Veritas Prep
Of the 60 families in a certain neighborhood, 38 have a cat. How many of the families in this neighborhood have a dog?
(1) 28 of the families in this neighborhood have a cat but not a dog
(2) The number of families in the neighborhood who have a dog and a cat is the same as the number of families who have neither a cat nor a dog.
Experts: only Veritas Prep experts, please!
68- n= 38+B- both
From 2 we know n = both so
68 = 38 + B
so B = 30
Ans B
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Glad to see that this one is still getting responses!!
Nice diagram ritzzzr!
This one is B, which is not totally expected right? Lots of people go for C. But this is a B - A - D subject. I actually wrote about this exact problem as part of a much larger article called "Data Sufficiency Jujitsu: Part 1.
https://www.beatthegmat.com/mba/2013/01/ ... d-subjects
Nice diagram ritzzzr!
This one is B, which is not totally expected right? Lots of people go for C. But this is a B - A - D subject. I actually wrote about this exact problem as part of a much larger article called "Data Sufficiency Jujitsu: Part 1.
https://www.beatthegmat.com/mba/2013/01/ ... d-subjects
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Source: Veritas Prep
Of the 60 families in a certain neighborhood, 38 have a cat. How many of the families in this neighborhood have a dog?
1. 28 of the families in this neighborhood have a cat but not a dog
2. The number of families in the neighborhood who have a dog and a cat is the same as the number of families who have neither a cat nor a dog.
Hi Here's my solutions to the problem:
Solution A Cats No Cats Total
Dogs 10 ?
No Dogs 28
Total 38 22 60
In-sufficient because "?" can't be determined.
Solution B Cats No Cats Total
Dogs x 22-x 22
No Dogs 38-x x 38
Total 38 22 60
In the above Cat & Dog = X and No Cat & No Dog = X
Sufficient because Dogs = 22.
Therefore the answer is B.
Of the 60 families in a certain neighborhood, 38 have a cat. How many of the families in this neighborhood have a dog?
1. 28 of the families in this neighborhood have a cat but not a dog
2. The number of families in the neighborhood who have a dog and a cat is the same as the number of families who have neither a cat nor a dog.
Hi Here's my solutions to the problem:
Solution A Cats No Cats Total
Dogs 10 ?
No Dogs 28
Total 38 22 60
In-sufficient because "?" can't be determined.
Solution B Cats No Cats Total
Dogs x 22-x 22
No Dogs 38-x x 38
Total 38 22 60
In the above Cat & Dog = X and No Cat & No Dog = X
Sufficient because Dogs = 22.
Therefore the answer is B.
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Pretty Easy?
It is better if you do not use that four-letter-word. As soon as you think something is easy, you miss it.
Here is an article about easy questions https://www.beatthegmat.com/mba/2012/12/ ... n-the-gmat
It is better if you do not use that four-letter-word. As soon as you think something is easy, you miss it.
Here is an article about easy questions https://www.beatthegmat.com/mba/2012/12/ ... n-the-gmat
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Nicely explained David Thanks!
David@VeritasPrep wrote:OA is B.
The explanations above are correct. For those who need a little slower paced explanation as to why B works, the following gives some more detail.
Correct answer: (B)
Solution: On any Venn diagram problem it is helpful to draw out the two sets and also note the formula Total = Set 1 + Set 2 - Both + Neither. The question stem tells us that the total number of families is 60 and the total number of families with a cat is 38. The question is asking whether we can determine the total number of families who have a dog.
Statement (1) tells us that 28 families have a cat but not a dog. If there are 38 families in total that have a cat, this information tells you that 10 families (38-28) must have both a dog and a cat. It does not, however, give you any information about the number of families who have only a dog or neither a dog nor a cat. It is therefore impossible to determine how many total families have a dog. Note that because the question stem does not say that all the familes own a cat, a dog, or both, some households could own neither.
Statement (2) tells us that the number of families who have both a cat and a dog is the same as the number who have neither. This information does not appear to be sufficient at first glance but a closer look at the Venn diagram formula for two set problems shows that it is. Remember our formula from above: Total Familes = # of Families with a Cat (C) + #of Families with a Dog (D) - Families with Both (B) + Families with Neither (N). Or, with variables, T = C + D - B + N. Plug in the information from the question stem and Statement (2) to find that T = 60, C = 38, and B=N. We can then solve for D using the formula. 60 = 38 + D - B +B. D = 22. Statement (2) alone is sufficient.
So it was actually helpful that the information from the question stem gave the total families with cats and the question was asking about the total number of families with dogs. Because we are working with totals, the Both and the Neither Categories cancel out given the information in statement 2 that these two categories are equal.
Nice work guys!
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Probably 60th - 70th percentile, but it's from our books (not our online question sets) so I don't think we've determined an exact difficulty for it.Veera123 wrote:Thanks all for the good explanations.
What difficulty level would you rate this question?
That said, if you try our question bank at gmat.veritasprep.com, you can see the difficulties of each question, as determined by the number of people who've gotten them right so far (and which other questions those people answered correctly, in much the same way that the actual exam determines the difficulty of each question).
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