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Bob drives at an average rate of 50 mph from Berkeley to Los

Expert replies
by BTGmoderatorDC » Sun Sep 16, 2018 12:31 am
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Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

OA C

Source: Magoosh
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Source: — Problem Solving |

by Jay@ManhattanReview » Sun Sep 16, 2018 3:42 am
BTGmoderatorDC wrote:Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

OA C

Source: Magoosh
Distance = 350 miles
Average speed = 50 mph

Time taken = Distance/Speed

Total time taken = 350/50 = 7 hrs

The correct answer: C

Hope this helps!

-Jay
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by fskilnik@GMATH » Sun Sep 16, 2018 7:01 am
BTGmoderatorDC wrote:Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

Source: Magoosh
\[?\,\, = \,\,350\,\,{\text{miles}}\,\,\,\left( {\frac{{1\,\,\,{\text{h}}}}{{50\,\,{\text{miles}}}}\,\,\,\begin{array}{*{20}{c}}
\nearrow \\
\nearrow
\end{array}} \right)\,\,\,\, = 7\,\,{\text{h}}\]
Obs.: arrows indicate licit converter.

Trivial application of UNITS CONTROL, one of the most powerful tools of our course!


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
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by Brent@GMATPrepNow » Sun Sep 16, 2018 7:15 am
BTGmoderatorDC wrote:Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

OA C

Source: Magoosh
As the others have shown, the fast approach is to recognize that: travel time = distance/speed = 350/50 = 7 hours

However, we could also (if necessary) solve this by applying some common sense.

Bob's speed is 50 miles per hour.
In other words, for every 1 hour that elapses, Bob travels 50 miles

So, after 1 hour of traveling, Bob has traveled 50 miles
After 2 hours of traveling, Bob has traveled 100 miles
After 3 hours of traveling, Bob has traveled 150 miles
After 4 hours of traveling, Bob has traveled 200 miles
After 5 hours of traveling, Bob has traveled 250 miles
After 6 hours of traveling, Bob has traveled 300 miles
After 7 hours of traveling, Bob has traveled 350 miles

Answer: C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Scott@TargetTestPrep » Tue Sep 18, 2018 5:54 pm
BTGmoderatorDC wrote:Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

We can use the formula:

Average = total distance/total time

50 = 350/t

50t = 350

t = 7 hours

Answer: C

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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