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Register now and save up to $200 Available with Beat the GMAT members only code • Get 300+ Practice Questions 25 Video lessons and 6 Webinars for FREE Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • 5 Day FREE Trial Study Smarter, Not Harder Available with Beat the GMAT members only code ## batteries (OG) tagged by: Brent@GMATPrepNow This topic has 4 expert replies and 2 member replies razorback Junior | Next Rank: 30 Posts Joined 29 Aug 2011 Posted: 28 messages Upvotes: 1 #### batteries (OG) Mon Sep 19, 2011 5:20 pm A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold? (A) 3q/200 (read: 3q all over 200) (B) 3q/2 (read: 3q all over 2) (C) 150q (D) q/100 + 50 (read q over 100, then add 50) (E) 150/q Official answer soon. This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out. ### GMAT/MBA Expert Scott@TargetTestPrep GMAT Instructor Joined 25 Apr 2015 Posted: 891 messages Followed by: 6 members Upvotes: 43 Wed Jun 24, 2015 3:16 am razorback wrote: A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold? (A) 3q/200 (read: 3q all over 200) (B) 3q/2 (read: 3q all over 2) (C) 150q (D) q/100 + 50 (read q over 100, then add 50) (E) 150/q Official answer soon. This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out. Solution: We are given that 100 batteries cost a TOTAL of q dollars. We are also given that EACH battery was sold at 50% above the original cost. The first thing we must do is create an equation for q. Remember that q is the TOTAL COST. So if we make b = the original cost per battery we can say: 100 x b = q b = q/100 We now have the original cost per battery in terms of q. Next, we determine the selling price when we increase the cost by 50%. To calculate this increase we simply multiply q/100 by 1.5. We have: (q/100) x 1.5 (q/100) x 3/2 = 3q/200 Answer: A _________________ Scott Woodbury-Stewart Founder and CEO ### GMAT/MBA Expert Brent@GMATPrepNow GMAT Instructor Joined 08 Dec 2008 Posted: 11419 messages Followed by: 1229 members Upvotes: 5254 GMAT Score: 770 Wed Jun 24, 2015 6:20 am GMAT Prep Now's comprehensive video course can be used in conjunction with Beat The GMATâ€™s FREE 60-Day Study Guide and reach your target score in 2 months! ### GMAT/MBA Expert Anurag@Gurome GMAT Instructor Joined 02 Apr 2010 Posted: 3835 messages Followed by: 520 members Upvotes: 1854 GMAT Score: 770 Mon Sep 19, 2011 7:02 pm razorback wrote: A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold? (A) 3q/200 (read: 3q all over 200) (B) 3q/2 (read: 3q all over 2) (C) 150q (D) q/100 + 50 (read q over 100, then add 50) (E) 150/q Official answer soon. This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out. Cost of 100 batteries =$q
Cost of 1 battery = \$ (q/100)
It is given that the selling price of 1 battery is 50 percent above the original cost per battery, so the selling price of 1 battery = (q/100) + (q/100)*(50/100) = (q/100) + (q/200) = 3q/200

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GMATGuruNY GMAT Instructor
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Mon Sep 19, 2011 7:21 pm
razorback wrote:
A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

(A) 3q/200 (read: 3q all over 200)
(B) 3q/2 (read: 3q all over 2)
(C) 150q
(E) 150/q

This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
Let q = 200.
Thus, 100 batteries were bought for a total cost of 200.
Cost per battery = 200/100 = 2.
Selling price = 2 + .5(2) = 3. This is our target.

Now we plug q=200 into the answers to see which yields our target of 3.

3q/200 = (3*200)/200 = 3.

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razorback Junior | Next Rank: 30 Posts
Joined
29 Aug 2011
Posted:
28 messages
1
Thu Sep 22, 2011 7:01 pm
Ok that makes a lot of sense, thanks.

leumas Senior | Next Rank: 100 Posts
Joined
21 Aug 2011
Posted:
44 messages
3
Test Date:
12/28/2011
Target GMAT Score:
800
GMAT Score:
NA
Fri Sep 23, 2011 8:14 am
razorback wrote:
A dealer originally bought 100 identical batteries at a total cost of q dollars. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many dollars was each battery sold?

(A) 3q/200 (read: 3q all over 200)
(B) 3q/2 (read: 3q all over 2)
(C) 150q
(E) 150/q

This question is #84/230 from the Official Guide, which I interpret as "slightly below average" difficulty. I have stared down the explanation in the book and still can't grasp how this problem should be worked out.
Cost = q/100
Profit =50%
Selling price=1.5q/100
Answer doesn't have this option: Multiply by 2.

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