At a ceratin upscale restaurant, there just two kinds of

Let the number of entrees = x
Then the number of appetizers = 15-x
Since each entree item cost $30 and appetizer $12
then entree = $30
appetizer = 12 (15-x) = 180 - 12x
Last year, total food items = 15
Average price = $18
$$Average\ price=\frac{Total\ price\ of\ food}{Total\ food\ items}$$
$$18=\frac{Total\ price\ of\ food}{15}$$
$$Total\ price\ of\ food=18\cdot15=270$$
i.e entree price + appetizer price = 270
30x + 180 - 12x = 270
18x = 270 - 180
18x = 90
x = 90/18
x = 5
Last year restaurant had 5 entrees and 10 appetizers
Let the number of appetizers added this year = n
number of entree = 5
number of appetizers = 10+n
Each entree item = $30 and appetizer = $12
Hence, entree = 5*30 = 150, and appetizer = (10+n)*12
Appetizer = 120 + 12n
Average price = 15
$$15=\frac{Total}{5+10+n}$$
$$Total=15\left(15+n\right)=225+15n$$
entree price + appetizer price = 225 + 15n
150 + 120 + 12n = 225 + 15n
270 - 225 = 3n
$$n=\frac{45}{3}=15$$
(i.e they added 15 appetizers)

Answer = option E