A. 1.5
B. 2.5
C. 6
D. 10
E. 20
Answer: D
Source: Official Guide
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As shown in the diagram above, a lever resting on a fulcrum has weights of \(w_1\) pounds and \(w_2\) pounds, located
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Gmat_mission
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As shown in the diagram above, a lever resting on a fulcrum has weights of \(w_1\) pounds and \(w_2\) pounds, located \(d_1\) feet and \(d_2\) feet from the fulcrum. The lever is balanced and \(w_1d_1=w_2d_2.\) Suppose \(w_1\) is \(50\) pounds and \(w_2\) is \(30\) pounds. If \(d_1\) is \(4\) feet less than \(d_2,\) what is \(d_2,\) in feet?
A. 1.5
B. 2.5
C. 6
D. 10
E. 20
Answer: D
Source: Official Guide
A. 1.5
B. 2.5
C. 6
D. 10
E. 20
Answer: D
Source: Official Guide
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Solution:Gmat_mission wrote: ↑Tue Nov 10, 2020 8:10 amdiagram.jpg
As shown in the diagram above, a lever resting on a fulcrum has weights of \(w_1\) pounds and \(w_2\) pounds, located \(d_1\) feet and \(d_2\) feet from the fulcrum. The lever is balanced and \(w_1d_1=w_2d_2.\) Suppose \(w_1\) is \(50\) pounds and \(w_2\) is \(30\) pounds. If \(d_1\) is \(4\) feet less than \(d_2,\) what is \(d_2,\) in feet?
A. 1.5
B. 2.5
C. 6
D. 10
E. 20
Answer: D
Source: Official Guide
We are given that w(1) = 50, w(2) = 30, and d(1) = d(2) - 4. If we let d(2) = d, we have:
50 x (d - 4) = 30 x d
50d - 200 = 30d
20d = 200
d = 10
Answer: D
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