Arithmetic

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 214
Joined: Wed Nov 14, 2007 6:30 am
Thanked: 15 times

by sujaysolanki » Sat Dec 15, 2007 5:19 pm
I dont what you have done is completely wrong ..cud you post the options as well ..so that we cud solve it

Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Sat May 05, 2007 6:05 am
Thanked: 1 times

Re: Arithmetic

by srawat_itpro » Thu Dec 20, 2007 11:26 pm
Anonymous wrote:Can someone explain why multiplying both sides of the equation is incorrect if you want to remove the fraction in the denominator.

R = [24F/N]/[P+A/12]

I saw the following question on the GMAT Prep Software exam, and the question stated "Which of the following is an equivalent form of the formula?" My first step was to remove the fraction from the denominator by multiplying each expression by 12. When I did that I also mutliplied the equation on the left side, R, by 12. However, the final solution did not involve this step. The final solution only involved multiplying the numerator and denominator by 12. I always thought in order to maintain equality in any equation, whatever you did to one side of the equation you must do to the other side.

Any thoughts or ideas? Thanks again for sharing.
Hi

I believe its like this
R = [X]/[Y/Z]

What you are doing by multiplying each side with Z is something like:

ZR = [Z][[X]/[Y/Z]]
=> ZR = [Z][[XZ]/[Y]]
=> ZR = [XZ^2]/[Y]

So you see that what you are doing is actually not eliminating Z, but only further multiplying it.

Rgds
-Sandy
Decide and do it !!!

Master | Next Rank: 500 Posts
Posts: 315
Joined: Thu Aug 17, 2006 10:43 pm
Thanked: 23 times

by Suyog » Sat Dec 22, 2007 9:53 am
all the options are given for R...so just consider the R.H.S..

given - R = [24F/N]/[P+A/12]

= 24F / N * 12 / P+A

= 24F(12) / N(P + A)

= [288F]/ [PN+AN]

Ans D.

Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Sun Apr 15, 2007 6:48 am

by bacardi_blast » Sat Dec 22, 2007 9:58 pm
IMO answer is E

R = [24F/N] /[P + (A/12)]
= [24F/ N] /[12p + A]/ 12
= 24F *12 / N[12P + A]
= 288F/ 12PN + 12AN

Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Tue Jan 27, 2009 7:40 pm

by giambi » Thu Jun 23, 2011 5:48 am
Actually the answer doesn't have a 12 in the last AN.

R = [24F / N] / [P/1(12)+A/12] <=>
[24F/N]/[12P+A]/12 <=>
24F*12 / N (12P + A) <=>
288F / 12PN + AN

Hope this helps.
This is a block of text that can be added to posts you make.
There is a 1023 character limit

Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Sat May 28, 2011 7:00 am
Thanked: 2 times

by PencilNerd » Sat Jun 25, 2011 6:07 am
The answer is D. This is just testing the rule that when you have one fraction divided by another fraction you change the problem to multiplication and flip the second fraction. So instead of:
R = [24F/N] / [P+A/12], on the right side flip the second fraction and multiply:
R = [24F/N] * [12/P+A]

To multiply fractions just do top times top and bottom times bottom, so the above becomes:

R = [24F * 12] / [N * P+A] which simplifies to choice D:
R = 288F/[NP+NA]

User avatar
Legendary Member
Posts: 1255
Joined: Fri Nov 07, 2008 2:08 pm
Location: St. Louis
Thanked: 312 times
Followed by:90 members

by Tani » Sat Jun 25, 2011 7:29 am
When you multiply both the top and bottom of a fraction by x, you are essentially multiplying by x/x, which equals one. Therefore, you don't have to do anything to the other side since you haven't changed the value of the first side.
Tani Wolff