Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Area

Expert replies
by sampath » Tue Jul 05, 2011 10:45 pm
The center of the circle is at point (0,6). If the distance between the two points
where the circle intersects the x-axis is 16, what is the area of the circle?
Join the discussion
Source: — Problem Solving |

by edvhou812 » Tue Jul 05, 2011 10:56 pm
Is it 36pie? I'm thinking that the radius must be 6 since the center is six points up the y-axis, but that sounds too simple.
Join the discussion

by sampath » Tue Jul 05, 2011 11:13 pm
I don't think the answer is 36pi it is only the centre. To find the area , we have to determine the radius, which according to the Q stem can be derived from the two points at which the circle intersects at x axis, say (x,0) and (-x,0). The distance given between the two points is 16,
sqrt((2x)^2)=16 ===>x=2 or -2
Therefore, the two points are (2,0) and (-2,0). The radius will be then distance between (0,6)and (2,0)
or (0,6) and (-2,0) which gives sqrt(40). The area will then be 40pi.

But I am not sure whether this is the correct answer or the way to derive it. Need confirmation. Thanks.
Join the discussion

by sampath » Thu Jul 07, 2011 2:05 am
Could someone please help confirm the answer. Thanks.
Join the discussion

by shovan85 » Thu Jul 07, 2011 4:21 am
The center is at (0,6). The circle formed around this center has to be symmetrical against the Y-axis.

The distance between the two points intersecting X-axis is 16. So, we can say the length of the chord is 16.

The distance of any of the points from origin (0,0) is 8 as the circle is symmetric on Y-axis. (i.e the two intersecting points are (8,0) and (-8,0))

Now the radius = sqrt(6^2 + 8^2) = 10

Thus, the area = 100 * pie
If the problem is Easy Respect it, if the problem is tough Attack it
Join the discussion

by mayank82 » Thu Jul 07, 2011 6:55 am
if you draw a triangle using center O and two points of intersection call it A and B.
then you get a isoceles triangle since both OA and OB are radius so OA=OB.
And since center is 0,6 which means - Y axis divides AB symterically at 90 degress using pythagorous theorum (hyp) OA=sqrt(6^2 + 8^2) = 10

Area= Pie *10^2=100pie
Join the discussion

by winniethepooh » Thu Jul 07, 2011 9:23 am
@ sampath, why is the answer not 16 pie?
whats the OA?
Join the discussion

by mayank82 » Thu Jul 07, 2011 4:58 pm
@wtp: A and B are two points where circle intersects with x axis and since they are at the circumfrence of the circle and O is the center then OA = OB = radius of the circle.
Join the discussion

by amit2k9 » Thu Jul 07, 2011 11:41 pm
doing a bit of construction we have triangles with 6,8 and r as sides.

thus r=10 hence A = pi* 100.
For Understanding Sustainability,Green Businesses and Social Entrepreneurship visit -https://aamthoughts.blocked/
(Featured Best Green Site Worldwide-https://bloggers.com/green/popular/page2)
Join the discussion

by worldpeace93 » Fri Jul 08, 2011 1:57 am
Image

SO answer comes to 292pi.

Can somebody verify this Please?
Join the discussion

by Frankenstein » Fri Jul 08, 2011 2:03 am
worldpeace93 wrote:Image

SO answer comes to 292pi.

Can somebody verify this Please?
Hi,
You are calculating r^2 = 6^2 + 16^2 instead of r^2 = 6^2 + 8^2.
Cheers!

Things are not what they appear to be... nor are they otherwise
Join the discussion

by shovan85 » Fri Jul 08, 2011 2:14 am
worldpeace93 wrote:Image

SO answer comes to 292pi.

Can somebody verify this Please?
Image
If the problem is Easy Respect it, if the problem is tough Attack it
Join the discussion