In the figure attached, the radius of the circle with center O is 1 and BC=1. What is the area of triangular region ABC?
a) square root of 2 /2
b) square root of 3 /2
c) 1
d) square root of 2
e) square root of 3
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Area of triangular region
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chetanojha
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Check image.ferpape wrote:Im not sure how you calculated the area of CA??
I'll appriciate your comments.
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Answer is B. Explanation:
AC^2 - BC^2 = AB^2
(2)^2 - (1)^2 = 4 - 1 = 3 = square root of 3
Therefore, area of the triangle = 1/2 X Base X Height
= 1/2 X 1 X square root of 3
AC^2 - BC^2 = AB^2
(2)^2 - (1)^2 = 4 - 1 = 3 = square root of 3
Therefore, area of the triangle = 1/2 X Base X Height
= 1/2 X 1 X square root of 3
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