BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

AP-IV

Expert replies
by maihuna » Sun Aug 16, 2009 3:48 am
If S1, S2, S3, ... , S50 are the sums of 20 terms of AP series whose first terms are 1, 2, 3, 4, ..., and whose common difference are 1,3,5,7,...what is the value of:

S1+S2+S3+..+S50
Charged up again to beat the beast :)
Join the discussion
Source: — Problem Solving |

Re: AP-IV

by Morgoth » Sun Aug 16, 2009 4:11 am
maihuna wrote:If S1, S2, S3, ... , S50 are the sums of 20 terms of AP series whose first terms are 1, 2, 3, 4, ..., and whose common difference are 1,3,5,7,...what is the value of:

S1+S2+S3+..+S50
S1, first term = 1, common difference = 1, no. of terms = 20

S2, first term = 2, common difference = 2, no. of terms = 20

so on and so forth.

sum of S1 = 20/2 [ 2*1 + (19)1]
sum of S2 = 20/2 [ 2*2 + (19)2]
sum of S3 = 20/2 [ 2*3 + (19)3]

so on and so forth

now you can easily identify the pattern

10[2+19] * [1+2+3+4+5.....+50]

10*21*1275 = 210*1275
Join the discussion

by kaulnikhil » Thu Aug 20, 2009 8:50 am
is it 487750??
Join the discussion

by real2008 » Thu Aug 20, 2009 10:35 am
is it 500500
Join the discussion