Two ants leave simultaneously from a spot on the floor. One of them crawls due north at 2 inches per second, and the other crawls due west at a rate one-third faster than the first ant's rate. Approximately how many feet apart will they be after 6 seconds?
A. 83
B. 1
C. 1.33
D. 1.67
E. 20
I chose C
Would appreciate it if someone could throw some light on why it is wrong.
Kushal
Ant trouble
This topic has expert replies
-
- Senior | Next Rank: 100 Posts
- Posts: 80
- Joined: Thu Aug 12, 2010 11:47 pm
- Location: chennai, india
- Thanked: 2 times
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
1/3 faster means a rate that is 4/3 of the slower rate. Since the slower rate is 2 inches second, the faster rate is (4/3)*2 = 8/3 inches per second. Since the ants are traveling for the same amount of time, a rate that is 4/3 faster will result in a distance that is 4/3 of the shorter distance.kushal.adhia wrote:Two ants leave simultaneously from a spot on the floor. One of them crawls due north at 2 inches per second, and the other crawls due west at a rate one-third faster than the first ant's rate. Approximately how many feet apart will they be after 6 seconds?
A. 83
B. 1
C. 1.33
D. 1.67
E. 20
I chose C
Would appreciate it if someone could throw some light on why it is wrong.
Kushal
Distance north = r*t = 2*6 = 12.
Distance west = (4/3)*12 = 16.
These two distances form the legs of a right triangle. The distance between the ants is the hypotenuse. This right triangle is a multiple of a 3:4:5 triangle. 4*(3:4:5) = 12:16:20. Thus, the hypotenuse -- which is the distance between the ants -- is 20 inches.
The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
1/3 faster means a rate that is 4/3 of the slower rate. Since the slower rate is 2 inches per second, the faster rate is (4/3)*2 = 8/3 inches per second. Since the ants are traveling for the same amount of time, a rate that is 4/3 faster will result in a distance that is 4/3 of the shorter distance.kushal.adhia wrote:Two ants leave simultaneously from a spot on the floor. One of them crawls due north at 2 inches per second, and the other crawls due west at a rate one-third faster than the first ant's rate. Approximately how many feet apart will they be after 6 seconds?
A. 83
B. 1
C. 1.33
D. 1.67
E. 20
I chose C
Would appreciate it if someone could throw some light on why it is wrong.
Kushal
Distance north = r*t = 2*6 = 12.
Distance west = (4/3)*12 = 16.
These two distances form the legs of a right triangle. The distance between the ants is the hypotenuse. This right triangle is a multiple of a 3:4:5 triangle. 4*(3:4:5) = 12:16:20. Thus, the hypotenuse -- which is the distance between the ants -- is 20 inches. Since 12 inches = 1 foot, 20/12 = 5/3 = 1.67 feet.
The correct answer is D.
Last edited by GMATGuruNY on Mon Nov 08, 2010 12:05 pm, edited 2 times in total.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
- ikaplan
- Master | Next Rank: 500 Posts
- Posts: 181
- Joined: Fri Sep 04, 2009 12:06 pm
- Thanked: 17 times
- Followed by:1 members
Use Pythagorean theorem to solve this problem.
The paths of the two ants represent 2 sides of a right triangle. The distance between two ants is in fact the hypotenuse of the triangle.
The first ants (heading north) will travel 12 inches for 6 seconds (6 seconds * 2 inches/second= 12 inches)
The second ant (heading west) will travel 16 inches for the same time (rate: 2+1/3*2=8/3; 6 seconds * 8/3= 16 inches)
Therefore, the distance between two ants after 6 seconds equals:
d^2=12^2 + 16^2
d= SQRT (144+256)
d= SQRT (400)
d= 20
My answer is E (20).
The paths of the two ants represent 2 sides of a right triangle. The distance between two ants is in fact the hypotenuse of the triangle.
The first ants (heading north) will travel 12 inches for 6 seconds (6 seconds * 2 inches/second= 12 inches)
The second ant (heading west) will travel 16 inches for the same time (rate: 2+1/3*2=8/3; 6 seconds * 8/3= 16 inches)
Therefore, the distance between two ants after 6 seconds equals:
d^2=12^2 + 16^2
d= SQRT (144+256)
d= SQRT (400)
d= 20
My answer is E (20).
- MAAJ
- Master | Next Rank: 500 Posts
- Posts: 243
- Joined: Sun Jul 12, 2009 7:12 am
- Location: Dominican Republic
- Thanked: 31 times
- Followed by:2 members
- GMAT Score:480
The hyppotenuse is 20 inches but it asks "how many feet apart will they be after 6 seconds". Because 1 foot = 12 inches, the answer would be 20/12 = 1.67 which is Answer (D).
However I dont know if its a typo of the question stem because a real Gmat question would make reference to the relationship between a foot and an inch.
However I dont know if its a typo of the question stem because a real Gmat question would make reference to the relationship between a foot and an inch.