If p:q = (3/7):2 and q:r = 7:(11/2), what is the value of p + q + r?
I. The value of q is equal to the sum of p and r.
II. p + 3 q - 2 r = 23.
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the value of p + q + r?
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- sanju09
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If p:q = (3/7):2 and q:r = 7:(11/2), what is the value of p + q + r?
The question can be rephrased to if p:q:r = 3:14:11 then what is the value of p + q + r?
p = 3x
q = 14x
r = 11x
q = p+q => 14x = 14x. Since, we still are not aware of the value of x, Statement 1 is insufficient to answer the question
IMO B
The question can be rephrased to if p:q:r = 3:14:11 then what is the value of p + q + r?
Since p:q:r = 3:14:11, we can represent p,q,r in terms of x(x = a positive integer)I.The value of q is equal to the sum of p and r.
p = 3x
q = 14x
r = 11x
q = p+q => 14x = 14x. Since, we still are not aware of the value of x, Statement 1 is insufficient to answer the question
p + 3 q - 2 r = 3x + (3*14x) - (2*11x) = 23x = 23. Implies x = 1 and p+q+r=3+14+11=28. Statement 1 is sufficient to answer the questionII.p + 3 q - 2 r = 23.
IMO B
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Well very intelligent question but not difficult...
From simultaneous equations perspective, the answer comes down to be C, as you need 2 equations...
But B alone can give the answer...
Statement 1 alone is absolutely insufficient to provide with an answer...
Statement 2:
(p:q:r) = (3:14:11)
let x be the common element between then,
p = 3x ; q = 14x ; r = 11x
now putting the values in the second equation, we get
23x = 23 hence x = 1
when x =1, the total of (p+q+r) = 28 which is the right answer...
THa OA is B.
Please give the OA asap...
From simultaneous equations perspective, the answer comes down to be C, as you need 2 equations...
But B alone can give the answer...
Statement 1 alone is absolutely insufficient to provide with an answer...
Statement 2:
(p:q:r) = (3:14:11)
let x be the common element between then,
p = 3x ; q = 14x ; r = 11x
now putting the values in the second equation, we get
23x = 23 hence x = 1
when x =1, the total of (p+q+r) = 28 which is the right answer...
THa OA is B.
Please give the OA asap...
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Actually statement 1 creates situation like 14x = 14x which is not a valid equation by itself...
Hence statement 1 is insufficient...
Hence statement 1 is insufficient...
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I received a PM asking me to comment.sanju09 wrote:If p:q = (3/7):2 and q:r = 7:(11/2), what is the value of p + q + r?
I. The value of q is equal to the sum of p and r.
II. p + 3 q - 2 r = 23.
[spoiler]made up by Sanjeev K Saxena for Avenues Abroad[/spoiler]
To combine ratios with a common element, the common element must be represented by the same value in each ratio.
p:q = (3/7) : 2 = 3:14.
q:r = 7 : (11/2) = 14:11.
Combining the ratios:
p:q:r = 3:14:11.
Statement 1: q = p+r.
No new information here.
In p:q:r = 3:14:11, p+r = 3+11 = 14, which is the value of q.
Thus, given ANY combination that satisfies p:q:r = 3:14:11, q=p+r.
If the values in the ratio are doubled so that p=6, q=28, and r=22, q=p+r.
If the values in the ratio are tripled so that p=9, q=42 and r=33, q=p+r.
Since an infinite number of combinations are possible, no way to determine p+q+r.
INSUFFICIENT.
Statement 2: p + 3q - 2r = 23.
This equation is satisfied by the values in the ratio.
If p=3, q=14, and r=11, then p + 3q - 2r3 + 3(14) - 2(11) = 23.
Thus, this is the ONLY combination that will work here.
Any MULTIPLE of 3:11:14 will yield a MULTIPLE of 23.
Thus, p+q+r = 3+14+11 = 28.
SUFFICIENT.
The correct answer is B.
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As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
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