BTGModeratorVI wrote: ↑Sun Jul 26, 2020 6:42 am
An “Armstrong number” is an n-digit number that is equal to the sum of the nth powers of its individual digits. For example, 153 is an Armstrong number because it has 3 digits and 1^3 + 5^3 + 3^3 = 153. What is the digit k in the Armstrong number 1,6k4 ?
A. 2
B. 3
C. 4
D. 5
E. 6
Answer:
B
Source: Official guide
So, as per the given information, we have 1,6k4 = 1^4 + 6^4 + k^4 + 4^4
1,6k4 = 1 + 1,296 + k^4 + 256
1,6k4 = 1,553 + k^4
1,000 + 600 + 10k + 4 = 1,553 + k^4
1,604 – 1,553 + 10k = k^4
51 + 10k = k^4
Now solving this higher-order equation is a tedious task. Let's make things easier by analyzing options.
Note that irrespective of the value of k, the units digits of 10k would be 0. Thus, the units digits of 51 = 10k would be 1. This means that the units digits of k^4 is also 1.
Only option B (= 3) qualifies as 3^4 = 81, the units digits = 1.
Correct answer:
B
Hope this helps!
-Jay
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