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All actors are exuberant

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by madhur_ahuja » Mon Aug 10, 2009 8:58 pm
All actors are exuberant people and all exuberant people are extroverts, but nevertheless it is true that some shy people are actors.
If the statements above are true, each of the following must also be true EXCEPT:

(A) Some shy people are extroverts.
(B) Some shy extroverts are not actors.
(C) Some exuberant people who are actors are shy.
(D) All people who are not extroverts are not actors.
(E) Some extroverts are shy
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by italian7745 » Tue Aug 11, 2009 1:33 am
IMO B
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by scoobydooby » Tue Aug 11, 2009 7:16 am
would go with C

all actors=exuberant
all exuberant=extrovert (not shy)
=>all actors are non shy

C says some actors are shy. contradicts the stimulus.
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by madhur_ahuja » Tue Aug 11, 2009 7:20 am
scoobydooby wrote:would go with C

all actors=exuberant
all exuberant=extrovert (not shy)
=>all actors are non shy

C says some actors are shy. contradicts the stimulus.
Hi Sciobydooby

How did you derive this ? :
all exuberant=extrovert (not shy)
=>all actors are non shy
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by real2008 » Tue Aug 11, 2009 8:50 am
IMO B
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by madhur_ahuja » Tue Aug 11, 2009 8:56 am
Please give reasonings.
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by scoobydooby » Tue Aug 11, 2009 9:36 am
madhur_ahuja wrote:
scoobydooby wrote:would go with C

all actors=exuberant
all exuberant=extrovert (not shy)
=>all actors are non shy

C says some actors are shy. contradicts the stimulus.
Hi Sciobydooby

How did you derive this ? :
all exuberant=extrovert (not shy)
=>all actors are non shy
yes right, it doesnt quite work. i had missed out on "some shy are actors"
i tried using sets, i seem to get C again

attaching the diagram
Last edited by scoobydooby on Tue Aug 11, 2009 10:09 am, edited 1 time in total.
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by madhur_ahuja » Tue Aug 11, 2009 9:59 am
scoobydooby wrote:
madhur_ahuja wrote:
scoobydooby wrote:would go with C

all actors=exuberant
all exuberant=extrovert (not shy)
=>all actors are non shy

C says some actors are shy. contradicts the stimulus.
Hi Sciobydooby

How did you derive this ? :
all exuberant=extrovert (not shy)
=>all actors are non shy
yes right, it doesnt quite work. i had missed out on "some shy are actors"
i tried using sets, i seem to get C again

attaching the diagram
According to your diagram, C should be TRUE since there is an overlap on exuberant, actors and shy.

Anyway, I don't think representation of shy is correct in the diagram.

OA is B and this is due to process of elimination. You cannot prove B but every other option can be proved by the premises present in the argument.
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by scoobydooby » Tue Aug 11, 2009 10:07 am
i should just guess on such questions :)
real2008 and italian7745, please share your thoughts/reasoning on B.
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by shark » Tue Aug 11, 2009 10:10 am
What about D?

All Actors --> Exuberants
All Exuberant --> Extroverts

Some Shy --> Actors
Some Shy who are actors --> Exuberants --> Extroverts

So, I eliminated (A), (B), (E).
I am left with (C) and (D).
I could also eliminate (C).

(D) is stating the opposite of the given data, i.e. All Non-Extroverts --> Not Actors?

I could be wrong, please correct me if i am so. Thank you.
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by madhur_ahuja » Tue Aug 11, 2009 10:23 am
shark wrote:What about D?


(D) is stating the opposite of the given data, i.e. All Non-Extroverts --> Not Actors?

.
This is what . D is too extreme, something you cannot say will hold true or not, since it is not stated in the passage.
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Re: All actors are exuberant

by real2008 » Tue Aug 11, 2009 10:42 am
madhur_ahuja wrote:All actors are exuberant people and all exuberant people are extroverts, but nevertheless it is true that some shy people are actors.
If the statements above are true, each of the following must also be true EXCEPT:

(A) Some shy people are extroverts.
(B) Some shy extroverts are not actors.
(C) Some exuberant people who are actors are shy.
(D) All people who are not extroverts are not actors.
(E) Some extroverts are shy
Please see attached the file. As per statement B, the red zone has to necessarily exist. But consider the only zone (i.e. shy people zone) with green and blue color and no red color and this holds the given condition in question. mind the qn is 'must be type'.
Attachments
untitled.JPG
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by kris77 » Sun May 15, 2016 3:16 pm
In my opinion B is the most logical one.
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