Q: If x = 3 + 3^2/3 + 3^ 1/3 , then the value of x^3 - 9x^2 + 18x - 12 is :
a) 1
b) 0
c) -1
d) 2^1/2
e) 3
a) 1
b) 0
c) -1
d) 2^1/2
e) 3
800. Arjun's-Bird-Eye
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Hi Praveen,kvcpk wrote:Hi Aman,
I think the options provided are wrong.. Correct me if i am doing any mistake in my procedure..
x^3 - 9x^2 + 18x - 12 equals (x-3)^3+15
x-3 = 3^2/3 + 3^ 1/3 as per the question, which is always positive.
So the value of x^3 - 9x^2 + 18x - 12 must be greater than 15.
Are you sure about the options?
Praveen.
You mentioned substituting value of x , but can you elaborate how we get to the answer 0.selango wrote:(x-3)^3=x3-9x2+27x-27
So x3-9x2+18x-12 = (x-3)^3-9x+15
Substituting value of x we will get answer 0
I am not sure whether we will get this kind of long algebra prob in real GMAT.