Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Algebra

Expert replies
by Aman verma » Tue Jun 01, 2010 12:43 am
Q: If x = 3 + 3^2/3 + 3^ 1/3 , then the value of x^3 - 9x^2 + 18x - 12 is :

a) 1

b) 0

c) -1

d) 2^1/2

e) 3
800. Arjun's-Bird-Eye
Join the discussion
Source: — Problem Solving |

by kvcpk » Tue Jun 01, 2010 2:09 am
Hi Aman,

I think the options provided are wrong.. Correct me if i am doing any mistake in my procedure..

x^3 - 9x^2 + 18x - 12 equals (x-3)^3+15
x-3 = 3^2/3 + 3^ 1/3 as per the question, which is always positive.

So the value of x^3 - 9x^2 + 18x - 12 must be greater than 15.

Are you sure about the options?

Praveen.
Join the discussion

by Aman verma » Tue Jun 01, 2010 2:52 am
kvcpk wrote:Hi Aman,

I think the options provided are wrong.. Correct me if i am doing any mistake in my procedure..

x^3 - 9x^2 + 18x - 12 equals (x-3)^3+15
x-3 = 3^2/3 + 3^ 1/3 as per the question, which is always positive.

So the value of x^3 - 9x^2 + 18x - 12 must be greater than 15.

Are you sure about the options?

Praveen.
Hi Praveen,

Thanks for the response ! Options are correct . The Official Answer is [spoiler]B) 0 [/spoiler]. This problem has got something to do with ( x + y + z )^3 though I don't have the solution or the Explanation , unfortunately! This is a practice assignment given in my class with only the OA provided & I'm trying to figure out the solution myself.I would really appreciate if anybody could provide a detail explanation !!
800. Arjun's-Bird-Eye
Join the discussion

by selango » Tue Jun 01, 2010 4:41 am
(x-3)^3=x3-9x2+27x-27

So x3-9x2+18x-12 = (x-3)^3-9x+15

Substituting value of x we will get answer 0


I am not sure whether we will get this kind of long algebra prob in real GMAT.
Join the discussion

by Gmat Bond » Tue Jun 01, 2010 8:07 am
selango wrote:(x-3)^3=x3-9x2+27x-27

So x3-9x2+18x-12 = (x-3)^3-9x+15

Substituting value of x we will get answer 0


I am not sure whether we will get this kind of long algebra prob in real GMAT.
You mentioned substituting value of x , but can you elaborate how we get to the answer 0.
The name is Bond, GMAT BOND !!
Join the discussion

by selango » Tue Jun 01, 2010 8:53 am
Well its a longer approach.But IMO these kind of prob wont appear in real GMAT.

Now coming to the prob.

We need to substitute value of x in the below statement,

(x-3)^3-9x+15

X=(3+3^1/3+3^2/3)

-->(3^1/3+3^2/3)^3-9(3+3^2/3+3^1/3)+15

Solve first term with power 3 using (a+b)^3 formula.

Now solve the equation by expanding it fully.

3^2+3^4/3+(6*3^2/3)+3^5/3+3+6*(3^1/3)-27-(9*3^2/3)-(9*3^1/3)+15

=3^2/3*(-3)+3^1/3*(-3)+3^4/3+3^5/3

=3^1/3[(-3^1/3) -3+ 3+3^4/3]

=-3^2/3+3^5/3=3^2/3[-1+1]

3^2/3*0=0




Hope this clarify
Join the discussion

by Aman verma » Wed Jun 02, 2010 1:19 am
My sincere thanks to Selango ! Agreed , this type of lengthy question may not appear on the actul GMAT but it's a good practice quetion, nevertheless . An extra effort never hurts anybody !!
800. Arjun's-Bird-Eye
Join the discussion