ab < ac
We have to compare b and c and
we have 'a' on both sides of the inequality.

If a is positive, we can divide with a on both sides of the inequality and its sign will not change.
Thus, if a > 0, b < c.

If a is negative, we can divide with a on both sides of the inequality and its sign will reverse.
Thus, if a < 0, b > c.

As we see, the relationship of b and c depends only on the sign of 'a'. If we know the sign of 'a', we can compare b and c and answer the question.

Statement(1):
The sign of a is known.
SUFFICIENT

Statement(2):
No information on a.
INSUFFICIENT

[spoiler](A)[/spoiler] is the answer.

a is negative
so b is greater

Hi Sekar,

I am not sure if I understood you very well.

All numbers less than zero are defined as 'negative numbers'.
So, if a < 0, 'a' is negative.
And, if a < 0, a cannot be 0.5

Yes, since a < 0 in Statement(1), b > c.

Does this help?

Looking for an Experts explanation here.

TIA,
GK

The question tests inequality rules.

Given ab < ac, we are asked whether B>C?

We cant simplify the inequality until we know the sign of "a".

(1)a<0, i.e a is negative, therefore we can cancel "a" and you must flip the sign (because you are dividing by a negative) ... therefore you get B > C.

(2) Given C < 0, we cant simplify any further.

IMO: A

@ aneesh, got it. Thanks again.

According to your question
a seems negative
so this makes b greater
Don't know whether it's correct or not,So please let me know the correct answer,If I am wrong.
statistics help

its correct