algebra

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algebra

by kksekar » Mon May 07, 2012 3:29 am
if ab is less than ac , which is greater, b or c ?
1. a is less than 0
2.c is less than 0

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by aneesh.kg » Mon May 07, 2012 3:51 am
ab < ac
We have to compare b and c and
we have 'a' on both sides of the inequality.

If a is positive, we can divide with a on both sides of the inequality and its sign will not change.
Thus, if a > 0, b < c.

If a is negative, we can divide with a on both sides of the inequality and its sign will reverse.
Thus, if a < 0, b > c.

As we see, the relationship of b and c depends only on the sign of 'a'. If we know the sign of 'a', we can compare b and c and answer the question.

Statement(1):
The sign of a is known.
SUFFICIENT

Statement(2):
No information on a.
INSUFFICIENT

[spoiler](A)[/spoiler] is the answer.
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by kksekar » Mon May 07, 2012 4:24 am
a is negative
so b is greater

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by aneesh.kg » Mon May 07, 2012 4:28 am
Hi Sekar,

I am not sure if I understood you very well.

All numbers less than zero are defined as 'negative numbers'.
So, if a < 0, 'a' is negative.
And, if a < 0, a cannot be 0.5

Yes, since a < 0 in Statement(1), b > c.

Does this help?
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by GmatKiss » Mon May 07, 2012 5:32 am
Looking for an Experts explanation here.

TIA,
GK

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by zueswoods » Mon May 07, 2012 8:22 am
The question tests inequality rules.

Given ab < ac, we are asked whether B>C?

We cant simplify the inequality until we know the sign of "a".

(1)a<0, i.e a is negative, therefore we can cancel "a" and you must flip the sign (because you are dividing by a negative) ... therefore you get B > C.

(2) Given C < 0, we cant simplify any further.

IMO: A

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by kksekar » Mon May 07, 2012 8:36 am
@ aneesh, got it. Thanks again.

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by amit28it » Tue May 08, 2012 12:13 am
According to your question
a seems negative
so this makes b greater
Don't know whether it's correct or not,So please let me know the correct answer,If I am wrong.
statistics help

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by kksekar » Thu May 10, 2012 8:13 am
its correct