Charles , a novice skier , skis downhill at 8 miles per hour. He is passed by Kiko , an experienced skier at 60 miles per hour . Exactly 1 mile after passing Charles , Kiko falls and stops . How many minutes after the fall will Charles reach Kiko ?
a. 5.5
b. 6
c . 6.5
d . 7
e . 7.5
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IMO E
We just need to calculate the time required by charles to cover a mile.
R T D
8 t 1
t=1/8 = 7.5/60
7.5 minutes.
We just need to calculate the time required by charles to cover a mile.
R T D
8 t 1
t=1/8 = 7.5/60
7.5 minutes.
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I did the same mistake by choosing 7.5 ,which is incorrectbblast wrote:IMO E
We just need to calculate the time required by charles to cover a mile.
R T D
8 t 1
t=1/8 = 7.5/60
7.5 minutes.
OA C
And I am unable to guesstimate the reason.
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Oh
The only thing I can work out here is as follows :
r t d for kiko
60 t 1
therefore
t=1/60 hrs = 1 min.
Now the 7.5 minutes which charles travels also includes the 1 minute for Kiko's travel.(as charles has not stopped when Kiko overtook him)
But we are being asked as to how much time after Kiko's fall charles reached the point, hence Kiko had travelled 1 minute and charles also 1 minute(covering some disctance) by the time kiko fell.
additional time travelled by charles = 7.5-1
= 6.5
woof tricky one. Good one infact
whats the source ?
The only thing I can work out here is as follows :
r t d for kiko
60 t 1
therefore
t=1/60 hrs = 1 min.
Now the 7.5 minutes which charles travels also includes the 1 minute for Kiko's travel.(as charles has not stopped when Kiko overtook him)
But we are being asked as to how much time after Kiko's fall charles reached the point, hence Kiko had travelled 1 minute and charles also 1 minute(covering some disctance) by the time kiko fell.
additional time travelled by charles = 7.5-1
= 6.5
woof tricky one. Good one infact
whats the source ?
Cheers !!
Quant 47-Striving for 50
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Quant 47-Striving for 50
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My gmat journey :
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While Kiko was reaching the point, Charles did covered a certain distance.
1] We know that Charles crashed 1 minute after he passed Kiko (60 miles/ hour = 1 miles / min)
We can determine the distance between Charles and Kiko at the moment of the crash with this function:
2] (60 m/h - 8 m/h) / 60 minutes * 1 minute
<=>52/60 * 1 minute = 0,8666 miles.
Since Charles is now immobile, we have to estimate how long it will take for Kiko to arrive on the crash zone:
3] We know Kiko travel at 8 miles/ hour that is to say 0,1333 miles/ minute.
Then, it will takes 0,86666 miles / 0,13333 miles(per minute) = 6,6 mins for Kiko to arrive on the crash zone
Answer C (but it is curious that it is not exactly the proposed answer)
(My apologizes for my poor english)
1] We know that Charles crashed 1 minute after he passed Kiko (60 miles/ hour = 1 miles / min)
We can determine the distance between Charles and Kiko at the moment of the crash with this function:
2] (60 m/h - 8 m/h) / 60 minutes * 1 minute
<=>52/60 * 1 minute = 0,8666 miles.
Since Charles is now immobile, we have to estimate how long it will take for Kiko to arrive on the crash zone:
3] We know Kiko travel at 8 miles/ hour that is to say 0,1333 miles/ minute.
Then, it will takes 0,86666 miles / 0,13333 miles(per minute) = 6,6 mins for Kiko to arrive on the crash zone
Answer C (but it is curious that it is not exactly the proposed answer)
(My apologizes for my poor english)
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i think my solution is correct Deepthi.Deepthi Subbu wrote:Source - Powerscorebblast wrote:woof tricky one. Good one infact
whats the source ?
any more such questions ??, very gmat like i say.
Cheers !!
Quant 47-Striving for 50
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Quant 47-Striving for 50
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Oh yes , your method is indeed correctbblast wrote:i think my solution is correct Deepthi.Deepthi Subbu wrote:Source - Powerscorebblast wrote:woof tricky one. Good one infact
whats the source ?
any more such questions ??, very gmat like i say.
I'l post more of such questions if I find them .
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Hi there,Deepthi Subbu wrote:Charles , a novice skier , skis downhill at 8 miles per hour. He is passed by Kiko , an experienced skier at 60 miles per hour . Exactly 1 mile after passing Charles , Kiko falls and stops . How many minutes after the fall will Charles reach Kiko ?
a. 5.5
b. 6
c . 6.5
d . 7
e . 7.5
How many minutes each one needs to run 1 mile?
> Kiko needs 1 mile / 60 mph = 1/60 h = 1 min
> Charles needs 1 mile / 8 mph = 1/8 h = 60/8 min = 7.5 min
The answer is therefore 6.5min, because Charles "used" the 1 min Kiko run till he (Kiko) fall!
Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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