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Expert replies
by Deepthi Subbu » Thu Jan 06, 2011 2:10 am
Charles , a novice skier , skis downhill at 8 miles per hour. He is passed by Kiko , an experienced skier at 60 miles per hour . Exactly 1 mile after passing Charles , Kiko falls and stops . How many minutes after the fall will Charles reach Kiko ?

a. 5.5
b. 6
c . 6.5
d . 7
e . 7.5
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Source: — Problem Solving |

by bblast » Thu Jan 06, 2011 3:03 am
IMO E

We just need to calculate the time required by charles to cover a mile.

R T D

8 t 1

t=1/8 = 7.5/60

7.5 minutes.
Cheers !!

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by Deepthi Subbu » Thu Jan 06, 2011 3:10 am
bblast wrote:IMO E

We just need to calculate the time required by charles to cover a mile.

R T D

8 t 1

t=1/8 = 7.5/60

7.5 minutes.
I did the same mistake by choosing 7.5 ,which is incorrect :(

OA C

And I am unable to guesstimate the reason.
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by bblast » Thu Jan 06, 2011 3:22 am
Oh

The only thing I can work out here is as follows :

r t d for kiko

60 t 1

therefore

t=1/60 hrs = 1 min.

Now the 7.5 minutes which charles travels also includes the 1 minute for Kiko's travel.(as charles has not stopped when Kiko overtook him)

But we are being asked as to how much time after Kiko's fall charles reached the point, hence Kiko had travelled 1 minute and charles also 1 minute(covering some disctance) by the time kiko fell.

additional time travelled by charles = 7.5-1
= 6.5

woof tricky one. Good one infact

whats the source ?
Cheers !!

Quant 47-Striving for 50
Verbal 34-Striving for 40

My gmat journey :
https://www.beatthegmat.com/710-bblast-s ... 90735.html
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How to prepare before your MBA:
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by mike34 » Thu Jan 06, 2011 7:11 am
While Kiko was reaching the point, Charles did covered a certain distance.

1] We know that Charles crashed 1 minute after he passed Kiko (60 miles/ hour = 1 miles / min)

We can determine the distance between Charles and Kiko at the moment of the crash with this function:

2] (60 m/h - 8 m/h) / 60 minutes * 1 minute

<=>52/60 * 1 minute = 0,8666 miles.

Since Charles is now immobile, we have to estimate how long it will take for Kiko to arrive on the crash zone:

3] We know Kiko travel at 8 miles/ hour that is to say 0,1333 miles/ minute.

Then, it will takes 0,86666 miles / 0,13333 miles(per minute) = 6,6 mins for Kiko to arrive on the crash zone

Answer C (but it is curious that it is not exactly the proposed answer)

(My apologizes for my poor english)
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by Deepthi Subbu » Thu Jan 06, 2011 7:28 pm
bblast wrote:woof tricky one. Good one infact

whats the source ?
Source - Powerscore
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by bblast » Thu Jan 06, 2011 8:38 pm
Deepthi Subbu wrote:
bblast wrote:woof tricky one. Good one infact

whats the source ?
Source - Powerscore
i think my solution is correct Deepthi. :)

any more such questions ??, very gmat like i say.
Cheers !!

Quant 47-Striving for 50
Verbal 34-Striving for 40

My gmat journey :
https://www.beatthegmat.com/710-bblast-s ... 90735.html
My take on the GMAT RC :
https://www.beatthegmat.com/ways-to-bbla ... 90808.html
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https://www.youtube.com/watch?v=upz46D7 ... TWBZF14TKW_
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by Deepthi Subbu » Fri Jan 07, 2011 2:29 am
bblast wrote:
Deepthi Subbu wrote:
bblast wrote:woof tricky one. Good one infact

whats the source ?
Source - Powerscore
i think my solution is correct Deepthi. :)

any more such questions ??, very gmat like i say.
Oh yes , your method is indeed correct :)

I'l post more of such questions if I find them .
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by fskilnik@GMATH » Mon Jan 10, 2011 12:16 pm
Deepthi Subbu wrote:Charles , a novice skier , skis downhill at 8 miles per hour. He is passed by Kiko , an experienced skier at 60 miles per hour . Exactly 1 mile after passing Charles , Kiko falls and stops . How many minutes after the fall will Charles reach Kiko ?

a. 5.5
b. 6
c . 6.5
d . 7
e . 7.5
Hi there,

How many minutes each one needs to run 1 mile?

> Kiko needs 1 mile / 60 mph = 1/60 h = 1 min
> Charles needs 1 mile / 8 mph = 1/8 h = 60/8 min = 7.5 min

The answer is therefore 6.5min, because Charles "used" the 1 min Kiko run till he (Kiko) fall!

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
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