A train travels from Albany to Syracuse, a distance of 120 miles, at the average rate of 50 miles per hour. The train then travels back to Albany from Syracuse. The total travelling time of the train is 5 hours and 24 minutes. What was the average rate of speed of the train on the return trip to Albany?
A. 60 miles per hour
B. 50 miles per hour
C. 48 miles per hour
D. 40 miles per hour
E. 35 miles per hour
The OA is D.
The total distance from Albany to Syracuse is, 120 miles, and the train travels at a rate of 50 miles per hour, that's mean that the time that the train spent from Albany to Syracuse is, 120 / 50 = 2.4 hour or 2 hours and 24 minutes.
If we know that the total travelling time of the train was 5 hours and 24 minutes, the time that the train spent from Syracuse to Albany will be, 5.4 - 2.4 = 3 hours.
Now, we can get the average rate of speed of the train on the return trip to Albany, will be 120 / 3 = 40 miles per hour.
Experts, is there another way to solve this PS question? Thanks.
A. 60 miles per hour
B. 50 miles per hour
C. 48 miles per hour
D. 40 miles per hour
E. 35 miles per hour
The OA is D.
The total distance from Albany to Syracuse is, 120 miles, and the train travels at a rate of 50 miles per hour, that's mean that the time that the train spent from Albany to Syracuse is, 120 / 50 = 2.4 hour or 2 hours and 24 minutes.
If we know that the total travelling time of the train was 5 hours and 24 minutes, the time that the train spent from Syracuse to Albany will be, 5.4 - 2.4 = 3 hours.
Now, we can get the average rate of speed of the train on the return trip to Albany, will be 120 / 3 = 40 miles per hour.
Experts, is there another way to solve this PS question? Thanks.
