A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat, what is the probability that the team will have exactly 2 women?
a- 1/14
b- 1/7
c- 2/7
d- 3/7
e- 1/2
Answer is D can someone please show how to solve in detail? Thanks
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A small company employs 3 men and 5 women. If a team ....
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shankar.ashwin
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For the first choice, we want any 3/8. For the second choice, we want any 2/7. For the third choice, we can any 5/6. For the last choice, we want any 4/5. The probability of one option is the product: 120/1680 = 1/14. So there is a 1/14 chance of getting "exactly" 2 men and 2 women.
But now we have to consider that we are choosing 2 men and 2 women from 4 slots total, so we have to do a combination to find the possible arrangements of these selections.
4! / 2! (4 - 2)! = 4 x 3 x 2 / 2 x 2 = 24/4 = 6 ways.
So we multiply 1/14 by 6 since any 6 arrangements will do: 1/14*6 = 6/14 = 3/7.
But now we have to consider that we are choosing 2 men and 2 women from 4 slots total, so we have to do a combination to find the possible arrangements of these selections.
4! / 2! (4 - 2)! = 4 x 3 x 2 / 2 x 2 = 24/4 = 6 ways.
So we multiply 1/14 by 6 since any 6 arrangements will do: 1/14*6 = 6/14 = 3/7.
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Probability = Number of ways an event can occur/ Total number of possible outcomesfactor26 wrote:A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat, what is the probability that the team will have exactly 2 women?
a- 1/14
b- 1/7
c- 2/7
d- 3/7
e- 1/2
Answer is D can someone please show how to solve in detail? Thanks
Total number of employees = 8
4 employees are to be selected randomly, so total number of possible outcomes = 8C4 = 8!/(8 - 4)! * 4! = 70
Now exactly 2 women are to be selected implies that there should be exactly 2 men, so number of ways of selecting exactly 2 women = 5C2 * 3C2 = [5!/(3! * 2!] * [3!/2!] = 10 * 3 = 30
Therefore, required probability = 30/70 = [spoiler]3/7[/spoiler]
The correct answer is D.
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@ GMATGURU NY - I posted a question to your prior post here:
https://www.beatthegmat.com/select-exact ... tml#444103
https://www.beatthegmat.com/select-exact ... tml#444103
