If \(\dfrac2{x+1}=\dfrac1{x-1},\) for \(x \ne 1\) and \(x \ne -1,\) then \(x =\)
A. -3
B. -2
C. 0
D. 2
E. 3
Answer: E
Source: Princeton Review
If \(\dfrac2{x+1}=\dfrac1{x-1},\) for \(x \ne 1\) and \(x \ne -1,\) then \(x =\)
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It's a simple arithmetic problem
\(\dfrac2{x+1}=\dfrac1{x-1}\)
So, 2(x-1) = 1(x+1)
So, 2x - 2 = x + 1
So, x = 3
Correct ans is E
\(\dfrac2{x+1}=\dfrac1{x-1}\)
So, 2(x-1) = 1(x+1)
So, 2x - 2 = x + 1
So, x = 3
Correct ans is E
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Solution:Gmat_mission wrote: ↑Thu Sep 10, 2020 12:39 amIf \(\dfrac2{x+1}=\dfrac1{x-1},\) for \(x \ne 1\) and \(x \ne -1,\) then \(x =\)
A. -3
B. -2
C. 0
D. 2
E. 3
Answer: E
Cross-multiplying, we have:
2x - 2 = x + 1
x = 3
Answer: E
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