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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## A right circular cone is inscribed in a hemisphere so that tagged by: AAPL ##### This topic has 1 expert reply and 0 member replies ### Top Member ## A right circular cone is inscribed in a hemisphere so that ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult Official Guide A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere? $$A.\ \sqrt{3}:1$$ $$B.\ 1:1$$ $$C.\ \frac{1}{2}:1$$ $$D.\ \sqrt{2}:1$$ $$E.\ 2:1$$ OA B. ### GMAT/MBA Expert GMAT Instructor Joined 25 Apr 2015 Posted: 2006 messages Followed by: 14 members Upvotes: 43 AAPL wrote: Official Guide A right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere. What is the ratio of the height of the cone to the radius of the hemisphere? $$A.\ \sqrt{3}:1$$ $$B.\ 1:1$$ $$C.\ \frac{1}{2}:1$$ $$D.\ \sqrt{2}:1$$ $$E.\ 2:1$$ If a right circular cone is inscribed in a hemisphere so that the base of the cone coincides with the base of the hemisphere, then the height of the cone is exactly the radius of the hemisphere. So the ratio is 1:1. Answer: B _________________ Scott Woodbury-Stewart Founder and CEO • Magoosh Study with Magoosh GMAT prep Available with Beat the GMAT members only code • 5 Day FREE Trial Study Smarter, Not Harder Available with Beat the GMAT members only code • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • FREE GMAT Exam Know how you'd score today for$0

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