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A mixture of "lean" ground beef (10% fat) and &quo

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by BTGmoderatorDC » Wed Apr 03, 2019 6:12 pm
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A mixture of "lean" ground beef (10% fat) and "super-lean" ground beef (3% fat) has a total fat content of 8%. What is the ratio of "lean" ground beef to "super-
lean" ground beef?

a) 5:2
b) 6:3
c) 1:2
d) 8:4
e) 2:3

OA A

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by Jay@ManhattanReview » Wed Apr 03, 2019 9:37 pm
BTGmoderatorDC wrote:A mixture of "lean" ground beef (10% fat) and "super-lean" ground beef (3% fat) has a total fat content of 8%. What is the ratio of "lean" ground beef to "super-
lean" ground beef?

a) 5:2
b) 6:3
c) 1:2
d) 8:4
e) 2:3

OA A

Source: Manhattan Prep
Say the quantity of "lean" ground beef = x units and the quantity of "super-lean" ground beef = y units; thus, we have to get the value of x : y.

10%x + 3%y = 8%*(x + y)
2%x = 5%y

x/y = 5 : 2

The correct answer: A

Hope this helps!

-Jay
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by deloitte247 » Sat Apr 06, 2019 3:01 pm
Let lean ground beef = x
Let super-lean ground beef = y
$$\left(10\%\ of\ x\right)\ +\left(3\%\ of\ y\right)=8\%\left(x+y\right)$$
Weighted average
$$\frac{\left(3-8\right)}{8-10}=\frac{5}{2}\ =\ 5:2$$
Answer is option A.

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by Scott@TargetTestPrep » Sun Apr 07, 2019 5:26 pm
BTGmoderatorDC wrote:A mixture of "lean" ground beef (10% fat) and "super-lean" ground beef (3% fat) has a total fat content of 8%. What is the ratio of "lean" ground beef to "super-
lean" ground beef?

a) 5:2
b) 6:3
c) 1:2
d) 8:4
e) 2:3

OA A

Source: Manhattan Prep
We can create the equation in which x = the amount of lean ground beef and y = the amount of super lean ground beef:

0.1x + 0.03y = 0.08(x + y)

10x + 3y = 8x + 8y

2x = 5y

x/y = 5/2

Answer: A

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