A mixture of "lean" ground beef (10% fat) and "super-lean" ground beef (3% fat) has a total fat content of 8%. What is the ratio of "lean" ground beef to "super-
lean" ground beef?
a) 5:2
b) 6:3
c) 1:2
d) 8:4
e) 2:3
OA A
Source: Manhattan Prep
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A mixture of "lean" ground beef (10% fat) and &quo
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BTGmoderatorDC
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Jay@ManhattanReview
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Say the quantity of "lean" ground beef = x units and the quantity of "super-lean" ground beef = y units; thus, we have to get the value of x : y.BTGmoderatorDC wrote:A mixture of "lean" ground beef (10% fat) and "super-lean" ground beef (3% fat) has a total fat content of 8%. What is the ratio of "lean" ground beef to "super-
lean" ground beef?
a) 5:2
b) 6:3
c) 1:2
d) 8:4
e) 2:3
OA A
Source: Manhattan Prep
10%x + 3%y = 8%*(x + y)
2%x = 5%y
x/y = 5 : 2
The correct answer: A
Hope this helps!
-Jay
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deloitte247
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Let lean ground beef = x
Let super-lean ground beef = y
$$\left(10\%\ of\ x\right)\ +\left(3\%\ of\ y\right)=8\%\left(x+y\right)$$
Weighted average
$$\frac{\left(3-8\right)}{8-10}=\frac{5}{2}\ =\ 5:2$$
Answer is option A.
Hope this comes easy to understand for you!<i class="em em---1"></i>
Let super-lean ground beef = y
$$\left(10\%\ of\ x\right)\ +\left(3\%\ of\ y\right)=8\%\left(x+y\right)$$
Weighted average
$$\frac{\left(3-8\right)}{8-10}=\frac{5}{2}\ =\ 5:2$$
Answer is option A.
Hope this comes easy to understand for you!<i class="em em---1"></i>
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Scott@TargetTestPrep
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We can create the equation in which x = the amount of lean ground beef and y = the amount of super lean ground beef:BTGmoderatorDC wrote:A mixture of "lean" ground beef (10% fat) and "super-lean" ground beef (3% fat) has a total fat content of 8%. What is the ratio of "lean" ground beef to "super-
lean" ground beef?
a) 5:2
b) 6:3
c) 1:2
d) 8:4
e) 2:3
OA A
Source: Manhattan Prep
0.1x + 0.03y = 0.08(x + y)
10x + 3y = 8x + 8y
2x = 5y
x/y = 5/2
Answer: A
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