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A drink holding 6 ounces of an alcoholic drink that...

tagged by: AAPL

This topic has 2 expert replies and 1 member reply

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AAPL Moderator
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A drink holding 6 ounces of an alcoholic drink that...

Fri Mar 02, 2018 3:18 pm
A drink holding 6 ounces of an alcoholic drink that is 1 part rum to 2 parts coke is added to a jug holding 32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke. What is the ratio of rum to coke in the resulting mixture?

A. 2:5
B. 5:14
C. 3:5
D. 4:7
E. 14:5

The OA is B.

Can I say

Add 6 ounces + 32 ounces = 38

So my ratio a:b will be such that a + b divides 38 equally

Looking at options we can see 14+5 = 19

But we have two options utilizing those numbers.

But if you look the ratios 1:2 of mixture 1 and 1:3 of mixture 2 then it's certain that coke will be higher

So correct answer should be 5:14 as ratio asked and given is rum: coke.

Is there a strategic approach to this PS question? Can any experts help me, please? Thanks!

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Rich.C@EMPOWERgmat.com Elite Legendary Member
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Fri Mar 02, 2018 5:55 pm
Hi AAPL,

We're told that a drink holding 6 ounces of an alcoholic drink that is 1 part rum to 2 parts coke is added to a jug holding 32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke. We're asked for the ratio of rum to coke in the resulting mixture.

Your logic to approaching this question is perfect. Since this question can be viewed as a Weighted Average, you can also use the averages of the two individual mixtures to eliminate answers. When combining a mix that is 1:2 with a mix that is 1:3, the OVERALL ratio will have to be 'between' those two ratios. For example, Answer C would be the equivalent of 1:1.6666, but that's NOT between 1:2 and 1:3, so that ratio is not a possible result; you can eliminate Answers D and E for the same reason. IF you were combining EQUAL amounts of the two mixes, then the ratio would end up 'in the middle' - 1:2.5 (which is the equivalent of 2:5). That doesn't happen here though - there's LOTS more of the 1:3 mix, so 2:5 cannot be the answer either. That leaves us with just one option: the correct answer.

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Rich

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GMATGuruNY GMAT Instructor
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Sat Mar 03, 2018 3:37 am
AAPL wrote:
A drink holding 6 ounces of an alcoholic drink that is 1 part rum to 2 parts coke is added to a jug holding 32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke. What is the ratio of rum to coke in the resulting mixture?

A. 2:5
B. 5:14
C. 3:5
D. 4:7
E. 14:5
6 ounces of an alcoholic drink is 1 part rum to 2 parts coke.
Since rum : coke = 1:2 = 2:4, this drink is composed of 2 ounces of rum and 4 ounces of coke, for a total of 6 ounces.

32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke
Since rum : coke = 1:3 = 8:24, this drink is composed of 8 ounces of rum and 24 ounces of coke, for a total of 32 ounces.

Mixture of the two drinks:
(total rum) : (total coke) = (2+8) : (4+24) = 10:28 = 5:14.

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swerve Master | Next Rank: 500 Posts
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Sat Mar 03, 2018 4:44 am
Hi AAPL,

Another way to solve this question can be,

.................................. Rum ..................... Coke ................. Total

First Drink .............. 2 ............................ 4 ..................... 6 (Ratio 1:2)

Second Drink ....... 8 ............................. 24 ................... 32 (Ratio 1:3)

Total ........................ 10 ........................... 28 ................... 38

Ratio = 10:28 = 5:14.

Regards!

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