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A drink holding 6 ounces of an alcoholic drink that...

by AAPL » Fri Mar 02, 2018 3:18 pm
A drink holding 6 ounces of an alcoholic drink that is 1 part rum to 2 parts coke is added to a jug holding 32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke. What is the ratio of rum to coke in the resulting mixture?

A. 2:5
B. 5:14
C. 3:5
D. 4:7
E. 14:5

The OA is B.

Can I say

Add 6 ounces + 32 ounces = 38

So my ratio a:b will be such that a + b divides 38 equally

Looking at options we can see 14+5 = 19

But we have two options utilizing those numbers.

But if you look the ratios 1:2 of mixture 1 and 1:3 of mixture 2 then it's certain that coke will be higher

So correct answer should be 5:14 as ratio asked and given is rum: coke.

Is there a strategic approach to this PS question? Can any experts help me, please? Thanks!
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by [email protected] » Fri Mar 02, 2018 5:55 pm
Hi AAPL,

We're told that a drink holding 6 ounces of an alcoholic drink that is 1 part rum to 2 parts coke is added to a jug holding 32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke. We're asked for the ratio of rum to coke in the resulting mixture.

Your logic to approaching this question is perfect. Since this question can be viewed as a Weighted Average, you can also use the averages of the two individual mixtures to eliminate answers. When combining a mix that is 1:2 with a mix that is 1:3, the OVERALL ratio will have to be 'between' those two ratios. For example, Answer C would be the equivalent of 1:1.6666, but that's NOT between 1:2 and 1:3, so that ratio is not a possible result; you can eliminate Answers D and E for the same reason. IF you were combining EQUAL amounts of the two mixes, then the ratio would end up 'in the middle' - 1:2.5 (which is the equivalent of 2:5). That doesn't happen here though - there's LOTS more of the 1:3 mix, so 2:5 cannot be the answer either. That leaves us with just one option: the correct answer.

Final Answer: B

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by GMATGuruNY » Sat Mar 03, 2018 3:37 am
AAPL wrote:A drink holding 6 ounces of an alcoholic drink that is 1 part rum to 2 parts coke is added to a jug holding 32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke. What is the ratio of rum to coke in the resulting mixture?

A. 2:5
B. 5:14
C. 3:5
D. 4:7
E. 14:5
6 ounces of an alcoholic drink is 1 part rum to 2 parts coke.
Since rum : coke = 1:2 = 2:4, this drink is composed of 2 ounces of rum and 4 ounces of coke, for a total of 6 ounces.

32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke
Since rum : coke = 1:3 = 8:24, this drink is composed of 8 ounces of rum and 24 ounces of coke, for a total of 32 ounces.

Mixture of the two drinks:
(total rum) : (total coke) = (2+8) : (4+24) = 10:28 = 5:14.

The correct answer is B.
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by swerve » Sat Mar 03, 2018 4:44 am
Hi AAPL,

Another way to solve this question can be,

.................................. Rum ..................... Coke ................. Total

First Drink .............. 2 ............................ 4 ..................... 6 (Ratio 1:2)

Second Drink ....... 8 ............................. 24 ................... 32 (Ratio 1:3)

Total ........................ 10 ........................... 28 ................... 38

Ratio = 10:28 = 5:14.

Regards!
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hi

by Scott@TargetTestPrep » Mon Jun 10, 2019 6:18 pm
AAPL wrote:A drink holding 6 ounces of an alcoholic drink that is 1 part rum to 2 parts coke is added to a jug holding 32 ounces of an alcoholic drink that is 1 part rum to 3 parts coke. What is the ratio of rum to coke in the resulting mixture?

A. 2:5
B. 5:14
C. 3:5
D. 4:7
E. 14:5
(1/3 x 6 + 1/4 x 32)/2/3 x 6 + 3/4 x 32)

(2 + 8)/(4 + 24)

10/28 = 5/14

Alternate Solution:

We start with 6 ounces of a drink that is 1/3 rum. We add it to 32 ounces that is1/4 rum. The result is a mixture of 6 + 32 = 38 ounces of x percent of rum.

Putting this information into an equation, we have:

6(1/3) + 32(1/4) = 0.38x

2 + 8 = 0.38x

10/0.38 = x

Since the percent of rum is 10/0.38, then the percent of coke is 28/0.38.

Thus, we can express the ratio of rum to coke as:

(10/0.38)/(28/0.38) = 10/28 = 5/14

Answer: B

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