A cyclist travels 20 miles at a speed of 15 miles per hour. If he returns along the same path and the entire trip takes 2 hours, at what speed did he return?
A. 15 mph
B. 20 mph
C. 22 mph
D. 30 mph
E. 34 mph
The OA is D.
I solve this PS question as follows,
A cyclist travels 20 miles at a speed of 15 miles per hour
Time taken while going= Distance/Speed = 20/15 hrs = (4/3)hrs
Total time = 2hours
Time taken while returning = total - time taken while going = 2 - 4/3 = (2/3)hrs
Distance = 20miles
Time = (2/3)hrs
Speed = Distance/Time = 20/ (2/3) = 30 miles/hr
So, Answer is D.
Please, can anyone explain another way to solve this question? Thanks!
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A cyclist travels 20 miles at a speed of 15 miles per hour.
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BTGmoderatorLU
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Jay@ManhattanReview
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This approach is fine and efficient.BTGmoderatorLU wrote:A cyclist travels 20 miles at a speed of 15 miles per hour. If he returns along the same path and the entire trip takes 2 hours, at what speed did he return?
A. 15 mph
B. 20 mph
C. 22 mph
D. 30 mph
E. 34 mph
The OA is D.
I solve this PS question as follows,
A cyclist travels 20 miles at a speed of 15 miles per hour
Time taken while going= Distance/Speed = 20/15 hrs = (4/3)hrs
Total time = 2hours
Time taken while returning = total - time taken while going = 2 - 4/3 = (2/3)hrs
Distance = 20miles
Time = (2/3)hrs
Speed = Distance/Time = 20/ (2/3) = 30 miles/hr
So, Answer is D.
Please, can anyone explain another way to solve this question? Thanks!
-Jay
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Jeff@TargetTestPrep
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We know that distance/rate = time. If we let the speed of the return trip = r, then our equation for the time for the entire trip is:BTGmoderatorLU wrote:A cyclist travels 20 miles at a speed of 15 miles per hour. If he returns along the same path and the entire trip takes 2 hours, at what speed did he return?
A. 15 mph
B. 20 mph
C. 22 mph
D. 30 mph
E. 34 mph
time going + time returning = 2 hours
20/15 + 20/r = 2
4/3 + 20/r = 2
Multiplying by 3r, we have:
4r + 60 = 6r
60 = 2r
30 = r
Answer: D
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