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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## A cyclist riding in fog overtakes a man walking... tagged by: BTGmoderatorLU ##### This topic has 2 expert replies and 1 member reply ### Top Member ## A cyclist riding in fog overtakes a man walking... A cyclist riding in fog overtakes a man walking at the speed of 3 km/h. If the man could see the cyclist for 4 minutes an up to a distance of 100m, what is the speed of the cyclist in km/h? A. 1.5 B. 2.5 C. 4.5 D. 5 E. 6 The OA is C. I try to solve it as follow, $$Dist=100m\ =\frac{1}{10}km.$$ $$Time=4\min=\frac{1}{15}hours.$$ $$rate=rate\ of\ cyclits\left(x\right)-rate\ of\ walking=x-3.$$ $$Time=\frac{Dist}{Speed}\ \Rightarrow \frac{\frac{1}{10}}{x-3}=\frac{1}{15}\ \Rightarrow x=4.5\.$$ Experts, any suggestion about this PS question? Thanks in advance. ### GMAT/MBA Expert Senior | Next Rank: 100 Posts Joined 16 Dec 2014 Posted: 94 messages Followed by: 4 members Upvotes: 2 GMAT Score: 770 Top Reply LUANDATO wrote: A cyclist riding in fog overtakes a man walking at the speed of 3 km/h. If the man could see the cyclist for 4 minutes an up to a distance of 100m, what is the speed of the cyclist in km/h? A. 1.5 B. 2.5 C. 4.5 D. 5 E. 6 The OA is C. I try to solve it as follow, $$Dist=100m\ =\frac{1}{10}km.$$ $$Time=4\min=\frac{1}{15}hours.$$ $$rate=rate\ of\ cyclits\left(x\right)-rate\ of\ walking=x-3.$$ $$Time=\frac{Dist}{Speed}\ \Rightarrow \frac{\frac{1}{10}}{x-3}=\frac{1}{15}\ \Rightarrow x=4.5\.$$ Experts, any suggestion about this PS question? Thanks in advance. Absolutely perfect - love the way to set up the parameters, wrote down your equation given the speed of the walker and derived the solution. I would have done it in the same way. As a challenge, what would be the answer if the person is walking towards the cyclist as opposed to the same direction? ### Top Member Legendary Member Joined 29 Oct 2017 Posted: 680 messages Followed by: 4 members Hi, In 4 minutes, the cyclist gains 100m on the person walking. So let's see how much does the man travel in 4 minutes at 3 km/h = (3000/60)*4 = 200m. If the man has traveled 200m, then the cyclist travels = 200m + 100m = 300m. So, his speed = (300/4)*(60/1000) = 4.5 km/h. Option C. Regards! ### GMAT/MBA Expert GMAT Instructor Joined 09 Apr 2015 Posted: 1461 messages Followed by: 17 members Upvotes: 39 LUANDATO wrote: A cyclist riding in fog overtakes a man walking at the speed of 3 km/h. If the man could see the cyclist for 4 minutes an up to a distance of 100m, what is the speed of the cyclist in km/h? A. 1.5 B. 2.5 C. 4.5 D. 5 E. 6 We see that the rate of the cyclist exceeds the rate of the man by 100 m in 4 minutes, or 25 m/min. We need to convert this into km/h: 25 m/min x 1 km/1000 m x 60 min/h = 1500/1000 km/h = 1.5 km/h If we let r = the rate of the cyclist in km/h, then r - 3 = 1.5 r = 4.5 Answer: C _________________ Jeffrey Miller Head of GMAT Instruction • Free Trial & Practice Exam BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code • 1 Hour Free BEAT THE GMAT EXCLUSIVE Available with Beat the GMAT members only code • Free Practice Test & Review How would you score if you took the GMAT Available with Beat the GMAT members only code • Magoosh Study with Magoosh GMAT prep Available with Beat the GMAT members only code • Get 300+ Practice Questions 25 Video lessons and 6 Webinars for FREE Available with Beat the GMAT members only code • 5 Day FREE Trial Study Smarter, Not Harder Available with Beat the GMAT members only code • 5-Day Free Trial 5-day free, full-access trial TTP Quant Available with Beat the GMAT members only code • Free Veritas GMAT Class Experience Lesson 1 Live Free Available with Beat the GMAT members only code • FREE GMAT Exam Know how you'd score today for$0

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