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A certain airline's fleet consisted of 60 type A planes

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by BTGModeratorVI » Wed Jul 29, 2020 2:53 pm
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A certain airline's fleet consisted of 60 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet?

A. 6
B. 7
C. 8
D. 9
E. 10

Answer: D
Source: GMAT prep
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Source: — Problem Solving |

BTGModeratorVI wrote: ↑
Wed Jul 29, 2020 2:53 pm
A certain airline's fleet consisted of 60 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet?

A. 6
B. 7
C. 8
D. 9
E. 10

Answer: D
Solution:

We are given that the fleet started with 60 type A planes. We are also given that the airline retired 3 of the type A planes and acquired 4 new type B planes each year. We need to determine how many years it took for the number of type A planes left in the airline's fleet to be less than 50 percent of the fleet. We can let n = the number of years it will take for this to occur.

The number of type A planes in the fleet can be expressed as 60 - 3n (because the fleet loses 3 type A planes each year). The total number of planes in the fleet is 60 - 3n + 4n, which takes into account the loss of 3 type A planes and addition of 4 type B planes each year.

We are interested in the number of years it will take until the number of type A planes is less than ½ the total planes in the fleet, as illustrated in the following equation:

60 - 3n < (60 - 3n + 4n) x ½

Multiplying the entire equation by 2, we have:

120 - 6n < 60 + n

-7n < -60

n > -60/-7

n > 8 4/7

Since n > 8 4/7, the smallest integer value n can be is 9.

Answer: D

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BTGModeratorVI wrote: ↑
Wed Jul 29, 2020 2:53 pm
A certain airline's fleet consisted of 60 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans. How many years did it take before the number of type A planes left in the airline's fleet was less than 50 percent of the fleet?

A. 6
B. 7
C. 8
D. 9
E. 10

Answer: D
Source: GMAT prep
Let \(x =\) number of years. Each year we lose \(3\) Type A planes and gain \(4\) Type B planes.

Since we start off with \(60\) type A planes and \(0\) Type B planes, the following equation would determine the point in time where Type A planes \(=\) Type B planes

\((60-3x) = 4x \ldots \) this comes to \(8 \frac{4}{7}\) years.

Since we are looking for the number of years (rounded to the nearest whole number) where \(< 50\%\) of the planes are of Type A, this must be \(> 8\) years.

Therefore, \(9\) years.
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120 - 6n < 60 + n
-7n < -60
n > -60/-7
n > 8 4/7

Answer: D
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Airline's fleet consisted of 60 type A planes at the beginning of 1980.
Pre 1980, A = 60 and B = 0

Starting with 1980, the airline retired 3 of the TYPE A planes and acquired 4 new type B plans.
1980, A = 57 and B = 4

If we look carefully then the total number of planes will be increasing by 1 every year as they are removing 3 of A type and adding 4 of B type.

All these sequences can form an Arithmetic Progression.
Starting with 1980, the total number of planes every year is: 61, 62 , 63 ... i.e. 61+ (n - 1) , where n is the number of years after 1980.

Similarly, the number of B type planes since 1980 would be: 4, 8 ,12 ... i.e. 4+(n-1)4 , where n is the number of years after 1980.

Now we need to find the number of years it took "before" A was <50% of fleet.

Let us first find the number of years it took for A to be < 50% of total
OR the number of years it took for B to be > 1/2 of total, i.e.

4 + (n-1)4 > (1/2) [ 61 + (n-1)4]
=> n > 9

But we know that is the number of years after 1980. But we need to include 1980 since the addition and subtraction of planes started from that year.

So number of years taken = 9 + 1 = 10
But we need to find the number of years 'before' , so 9

Answer D


Thanks,
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