smanstar wrote:GMATGuruNY wrote:smanstar wrote:Q
In how many ways can 5 letters be posted in 4 mail boxes , any letter can be posted in any mail box ??
How i tried to solve
5 letters each letter has 4 choices so 4*4*4*4*4 = 4^5 ways
but I get confused, when I tried to solve the same in this way
4 mail boxes each can accept 5 letters so 5*5*5*5 = 5^4 ways.
please help me out with the basic difference between the two approaches and secondly how to solve the same ??
There are fewer mailboxes than letters.
The result: while not every mailbox must contain a letter, EVERY LETTER MUST CHOOSE A MAILBOX.
Thus, we count from the perspective of the LETTERS.
For each of the five letters, there are 4 choices of mailbox:
4*4*4*4*4 = 4�.
thanks for the reply but I have a doubt again
If in a problem we have to distribute 10 coins to 3 children then it should be 3*3*3...*3 = 3^10 but I am not getting the answer .
Can you please also explain whats the difference between the two problems
How many ways can 10 different coins be distributed among 3 children?
Here, the coins are all DIFFERENT.
Thus, it matters whether Coin A goes to child 1, child 2, or child 3.
In this case, the number of options for each coin = 3. (Any of the 3 children.)
To combine the number of options for each coin, we multiply:
3*3*3*3*3*3*3*3*3*3 = 3¹�.
How many ways can 10 identical coins be distributed among 3 children?
Here, the coins are all IDENTICAL.
Thus, it DOESN'T matter whether Coin A goes to child 1, child 2, or child 3.
All that matters is HOW MANY coins each child receives.
For this sort of problem, I recommend the SEPARATOR method.
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