A carpenter constructed a rectangular sandbox with a
capacity of 10 cubic feet. If the carpenter were to
make a similar sandbox twice as long, twice as wide,
and twice as high as the fi rst sandbox, what would be
the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100
Please explain me the answer!
Easy BUT!!!! OG 12 problem!
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Say, the first sandbox is a feet long, b feet wide, and c feet high.soniadiana2011 wrote:A carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide, and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox?
Hence, volume of the first sandbox = abc = 10 cubic feet
Now, the second sandbox is 2a feet long, 2b feet wide, and 2c feet high.
Hence, volume of the second sandbox = (2a)*(2b)*(2c) = 8abc = 8*10 cubic feet = 80 cubic feet
The correct answer is D.
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If the edges of the initial box are a, b and c long, thensoniadiana2011 wrote:A carpenter constructed a rectangular sandbox with a
capacity of 10 cubic feet. If the carpenter were to
make a similar sandbox twice as long, twice as wide,
and twice as high as the fi rst sandbox, what would be
the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100
Please explain me the answer!
Volume = (a)(b)(c) = 10
If each of the dimensions is made twice, then the new lengths of the edges are 2a, 2b and 2c.
New Volume = (2a)(2b)(2c) = 8abc
Since abc = 10,
New Volume = 8*10 = 80 cubic feet
[spoiler](D)[/spoiler] is the answer.
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Hi All,
We're told that a carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. We're asked if the carpenter were to make a similar sandbox TWICE as long, TWICE as wide, and TWICE as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox. This question can be solved by TESTing VALUES.
IF... we make the 'starting dimensions' of the sandbox (1 ft.) x (2 ft.) x (5 ft.)....
then the new dimensions (after being doubled) would be: (2 ft.) x (4 ft.) x (10 ft.)
The capacity of the new sandbox would be (2)(4)(10) = 80 cubic feet
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
We're told that a carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. We're asked if the carpenter were to make a similar sandbox TWICE as long, TWICE as wide, and TWICE as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox. This question can be solved by TESTing VALUES.
IF... we make the 'starting dimensions' of the sandbox (1 ft.) x (2 ft.) x (5 ft.)....
then the new dimensions (after being doubled) would be: (2 ft.) x (4 ft.) x (10 ft.)
The capacity of the new sandbox would be (2)(4)(10) = 80 cubic feet
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
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We can let the dimensions of the original sandbox be L, W, and H. Thus we have L x W x H = 10 , and the new sandbox would have a capacity ofsoniadiana2011 wrote:A carpenter constructed a rectangular sandbox with a
capacity of 10 cubic feet. If the carpenter were to
make a similar sandbox twice as long, twice as wide,
and twice as high as the fi rst sandbox, what would be
the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100
2L x 2W x 2H = 8 x LWH = 8 x 10 = 80 cubic feet
Answer: D
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