#70 GMAT 2017
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Hi jmacym,
This question can be solved by TESTing VALUES. I'm going to give you a couple of hints to get you started (so that you can finish the problem on your own):
1) To start, choose a small value for P (try P = 2).
2) Next, solve for R.
3) Plug P = 2 into the answer choices (make sure to check all 5). Which of them equals the value for R that you solved for?
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Rich
This question can be solved by TESTing VALUES. I'm going to give you a couple of hints to get you started (so that you can finish the problem on your own):
1) To start, choose a small value for P (try P = 2).
2) Next, solve for R.
3) Plug P = 2 into the answer choices (make sure to check all 5). Which of them equals the value for R that you solved for?
GMAT assassins aren't born, they're made,
Rich
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Plug in for p and solve for r.If p≠0 and p - (1-p²)/p = r/p, then r = ?
A. p + 1
B. 2p - 1
C. p² + 1
D. 2p² - 1
E. p² + p - 1
Let p=2.
Substituting p=2 into p - (1-p²)/p = r/p, we get:
2 - (1-2²)/2 = r/2
2 - (-3/2) = r/2
7/2 = r/2
r = 7.
The target value is r=7.
Now plug p=2 into the answer choices to see which yields the target value of 7.
Only D works:
2p² - 1 = 2(2²) - 1 = 7.
The correct answer is D.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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Or do a little algebra. Multiply both sides by 'p' to get p*p - (1-p²) = rQuote:
If p≠0 and p - (1-p²)/p = r/p, then r = ?
A. p + 1
B. 2p - 1
C. p² + 1
D. 2p² - 1
E. p² + p - 1
Simplify: p^2 - 1 + p^2 = r
And we get 2p^2 -1 = r; Answer is D
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Multiplying both sides by p is probably the easiest first step:
p² - (1 - p²) = r
Then the negative sign is applied to both terms in the ( )'s, giving us:
p² - 1 -(-p²) = r
or
2p² - 1 = r
p² - (1 - p²) = r
Then the negative sign is applied to both terms in the ( )'s, giving us:
p² - 1 -(-p²) = r
or
2p² - 1 = r