If the average (arithmetic mean) of 5 different numbers is 12, what is the median of the 5 numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of the 4 numbers other than the median is equal to 45.
5 different numbers is 12
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I think the answer should be B.ska7945 wrote:If the average (arithmetic mean) of 5 different numbers is 12, what is the median of the 5 numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of the 4 numbers other than the median is equal to 45.
Mean = 12
Median = ?
Statement I
The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
Median = 1/3 * (60-x)
x could be any number less than 60, hence insufficient.
Statement II
The sum of the 4 numbers other than the median is equal to 45.
sum of 5 numbers = 60
sum of 4 numbers except for median = 45
median = 15
Sufficient.
Hence B is the answer.
whats the OA?
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IMO D.
Assume the sum of the other 4 numbers other than the median is x. And lets say the median is y.
(x+y)/5=12
x+y=60 (eqn A)
and statement 2 says that:
y = x/3 (eqn B)
Using equations A and B, you can solve for the median, y. Therefore statement 2 is sufficient on its own.
BlueMentor
Assume the sum of the other 4 numbers other than the median is x. And lets say the median is y.
(x+y)/5=12
x+y=60 (eqn A)
and statement 2 says that:
y = x/3 (eqn B)
Using equations A and B, you can solve for the median, y. Therefore statement 2 is sufficient on its own.
BlueMentor
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Sorry I made a typo here... it should be read statement 1, not statement 2.Assume the sum of the other 4 numbers other than the median is x. And lets say the median is y.
(x+y)/5=12
x+y=60 (eqn A)
and statement 2 says that:
y = x/3 (eqn B)
Using equations A and B, you can solve for the median, y. Therefore statement 2 is sufficient on its own.
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(1) tells you that the median is 1/3 the sum of the other 4 numbers.
other #s + median = 12 * 5
3 medians + median = 60
4 medians = 60
median = 15
other #s + median = 12 * 5
3 medians + median = 60
4 medians = 60
median = 15
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D for meska7945 wrote:If the average (arithmetic mean) of 5 different numbers is 12, what is the median of the 5 numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of the 4 numbers other than the median is equal to 45.
assume the numbers to X1, X2, Y ( median) , X3 , X4
statement 1.
(X1+ X2+ X3+ X4)= 1/ 3*Y.....................................a
Question stem says
X1+ X2+ Y+ X3+ X4 = 60..........................................b
a-b
60- 4Y = 0
y = 15
hence sufficient
statemnt 2.
The sum of the 4 numbers other than the median is equal to 45.
sum of 5 numbers = 60
sum of 4 numbers except for median = 45
median = 15
Sufficient.
hence D
do let me know if u have any doubts...
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D is right my mansudhir3127 wrote:D for meska7945 wrote:If the average (arithmetic mean) of 5 different numbers is 12, what is the median of the 5 numbers?
(1) The median of the 5 numbers is equal to 1/3 of the sum of the 4 numbers other than the median.
(2) The sum of the 4 numbers other than the median is equal to 45.
assume the numbers to X1, X2, Y ( median) , X3 , X4
statement 1.
(X1+ X2+ X3+ X4)= 1/ 3*Y.....................................a
Question stem says
X1+ X2+ Y+ X3+ X4 = 60..........................................b
a-b
60- 4Y = 0
y = 15
hence sufficient
statemnt 2.
The sum of the 4 numbers other than the median is equal to 45.
sum of 5 numbers = 60
sum of 4 numbers except for median = 45
median = 15
Sufficient.
hence D
do let me know if u have any doubts...