3-q20

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3-q20

by stubbornp » Sun Oct 12, 2008 10:58 am
20. In the figure above, line AC represents a seesaw that is touching level ground at point A. If B is the midpoint of AC, how far above the ground is point C?
(1) x = 30
(2) Point B is 5 feet above the ground.

Image

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Re: 3-q20

by parallel_chase » Sun Oct 12, 2008 12:19 pm
stubbornp wrote:20. In the figure above, line AC represents a seesaw that is touching level ground at point A. If B is the midpoint of AC, how far above the ground is point C?
(1) x = 30
(2) Point B is 5 feet above the ground.

Image

Answer should be C.

Statement I
We dont know the any side of the two triangles.

Statement II
We dont know the measurement of angle x, we only know that angle formed from C to the ground will be 90.

Combining I & II
B to the ground or height = 5
x = 30 degrees
now we have the formation of 30-60-90 right angle triangle

30 - 1
60 - sqrt3
90 - 2
30 degree angle = 5 feet

We can easily find AB
AB + BC = AC

we have another formation of 30-60-90 because from point C to the ground angle will be 90 degree.

We already have the length of AB, therefore we can find the height.

Sufficient.

Hence C.

OA?
No rest for the Wicked....

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by nitin86 » Sun Oct 12, 2008 7:36 pm
I think B

stmt 2

If H = height of point C and h = height of point B

From similar triangle,
H/h = AC/AB => 2 AB/ Ab = 2 , and hence H = 2h

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by stubbornp » Sun Oct 12, 2008 9:04 pm
oa B