i get 2^5 as the answer.
OA is 2^8. what am i doing wrong?? isnt the top 2^6?
2^(41)^2
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this one tripped me up to. i still don't really understand what the difference is between:
4^(3)^2 and (4^3)^2
so in the first its 4^9 and second its 4^6? i'm not sure why this doesn't make sense to me. what is the order of operations rule i am missing?
4^(3)^2 and (4^3)^2
so in the first its 4^9 and second its 4^6? i'm not sure why this doesn't make sense to me. what is the order of operations rule i am missing?

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its PEMBAS.
parantheses always come first.
so if you do the parantheses, that's (41)squared, which is 3squared, which is 9.
parantheses always come first.
so if you do the parantheses, that's (41)squared, which is 3squared, which is 9.
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Yes, you're correct.nk_81 wrote:I seek clarification....
as per the attachment 2^(41)^2 is different from (2^(41))^2 ...right? The answer of the latter is going to be 2^5...is it?
2^[(4  1)^2] = 2^9 ...... BUT ...... [2^(4  1)]^2 = 2^6
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In this case, we just need to watch out for the parathesis then. The position of the parathesis will decide the solution for such questions. Right?[email protected] wrote:Yes, you're correct.nk_81 wrote:I seek clarification....
as per the attachment 2^(41)^2 is different from (2^(41))^2 ...right? The answer of the latter is going to be 2^5...is it?
2^[(4  1)^2] = 2^9 ...... BUT ...... [2^(4  1)]^2 = 2^6
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Yes, it should be.RyanP wrote:Why do you just automatically take out the parenthesis after doing 41. Shouldn't it still be 2^(3)^2?
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If it should be that, then why is the answer 2^8 rather than 2^5? OG has it as 2^8[email protected] wrote:Yes, it should be.RyanP wrote:Why do you just automatically take out the parenthesis after doing 41. Shouldn't it still be 2^(3)^2?
2^(3)^2, the parenthesis is 3^2 which is 9 and gives (2^9)/(2^1) which is still 2^8RyanP wrote:If it should be that, then why is the answer 2^8 rather than 2^5? OG has it as 2^8[email protected] wrote:Yes, it should be.RyanP wrote:Why do you just automatically take out the parenthesis after doing 41. Shouldn't it still be 2^(3)^2?
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^Exactly. The parentheses tell us which base to raise to its exponent first.
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Hi all,
sorry to dig this thread out again. I am not 100% clear on how the rules are with regards to exponents of exponents  I thought it was always just a question of multiplying them (ie 2^4^3 = 2^12) but now it seems that the rules have changed.
I don't quite understand where the brackets have to be to do the 3^2 in this case instead of 3*2. It would be great if someone could explain WHEN to use ^ and when *.
I kind of got from the previous explanation that when the exponent and its exponent (in this case: (41)^2) are in brackets, then I need to do ^  i.e. 3^2. And if the base is in a bracket with the "first exponent" (in this case: 2^(41)) then I need to multiply the first and the second exponent (ie (41)^2 = 3*2).
Is this always the rule? Can someone confirm if I'm right here please?
Thanks in advance!
Kate
sorry to dig this thread out again. I am not 100% clear on how the rules are with regards to exponents of exponents  I thought it was always just a question of multiplying them (ie 2^4^3 = 2^12) but now it seems that the rules have changed.
I don't quite understand where the brackets have to be to do the 3^2 in this case instead of 3*2. It would be great if someone could explain WHEN to use ^ and when *.
I kind of got from the previous explanation that when the exponent and its exponent (in this case: (41)^2) are in brackets, then I need to do ^  i.e. 3^2. And if the base is in a bracket with the "first exponent" (in this case: 2^(41)) then I need to multiply the first and the second exponent (ie (41)^2 = 3*2).
Is this always the rule? Can someone confirm if I'm right here please?
Thanks in advance!
Kate