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## 11. If W +x <0, is w-y>0?

This topic has 14 member replies
mmgmat2008 Junior | Next Rank: 30 Posts
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#### 11. If W +x <0, is w-y>0?

Tue Dec 09, 2008 5:00 am
(1) x+y <0

I got this wrong. why not D for this question?

andy123 Senior | Next Rank: 100 Posts
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Mon Mar 14, 2011 1:58 am
2nd equation is easy:

Question prompt requires us to prooove: w-y > 0

which means: W > y ??

Option B: already gives the olution y

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Sun Mar 13, 2011 10:33 am
an interesting problem popped up today. I found answer which is not OA cited in the post, please contribute

... this question's title contains part of this DS, so I am copying/pasting the title of the post back into the post
w<-x OR x<-w. Is w>y?
st(1) x<-y --> as x<-w both -w and -y can be greater than y, BUT we don't know if if w>y Not Sufficient;
st(2) y as x<-w and x|x|. If w<0 then w lies to the right from y, i.e. -y<-w. If w>0 then w lies to the left of y again, i.e. y Combined st(1&2): x<-y and y -x>y U x>y suggest y<0 and |x|y and -w>y present (the same condition was met in statement 2 Alone) BUT we need to meet both conditions w>y AND -w<-y

IOM E

Quote:
If W +x <0, is w-y>0?
(1) x+y <0
(2) y
mmgmat2008 wrote:
(1) x+y <0

I got this wrong. why not D for this question?

_________________
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niraj_a Legendary Member
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Tue Dec 09, 2008 5:35 am
from the stem, they are asking if w > y

statement II gives you that info directly while statement I does not.

what's the source?

hwiya320 Senior | Next Rank: 100 Posts
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Tue Dec 09, 2008 7:19 am
mmgmat2008 wrote:
(1) x+y <0

I got this wrong. why not D for this question?
Stem is stating,
W + X < 0
W < -X or W > X,

1) x +y < 0
which means x < -Y or -X > Y
so we knew that -X is greater than W, and now we know that -X is greater than Y. That doesn't prove that W is greater than Y.

I think what you did was X > -Y then flip the sign and got rid of negative for ALL numbers, X < Y... I assume that's how you determined that W>Y>X?

This Q is from GMATPrep.

mmgmat2008 Junior | Next Rank: 30 Posts
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Wed Dec 10, 2008 9:19 am
This type of questions is my weakness.
Thanks for the answers. I will try to not make the same mistake tomorrow at my G day!

cramya Legendary Member
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Wed Dec 10, 2008 7:34 pm
Think of it this way.

No info about x,y,w are given (may or may not be integers)

Since w+x<0 is given all we know is either both are negative or one of them is negative and other positive with the abolsute value of the negative number greater than the absolute value of the positive number.

Given w+x<0

w+x<0 i.e w< - x Is w-y>0 or w > y

Stmt II(always try to pick the easier of the 2 statements - just my opinion)

y
Exactly what we need w>y

SUFF

Now its down to B) or D) .

This way u have increased the probability of answering the question right (50% prob)

Given w+x<0 i.e w < -x (1)

Stmt I

x+y <0 I.E X< - Y (2)

U can pick numbers here where w > y and where w < y satisfying (1) and (2)

INSUFF

Choose B)

chipbmk Senior | Next Rank: 100 Posts
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Mon Nov 23, 2009 4:02 pm
Why can we not do this for statement 1:

Given: W+X<0

Statement 1: X+Y<0

Given --> X+W<0
Statement 1--> X+Y<0
______ (subtract the statements)
= W-Y<0 or W
Doesnt that give you a definitive "no" to the question is w-y>0? or is w>y? appears like it does to me ... let me know

mehravikas Legendary Member
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Tue Nov 24, 2009 6:36 pm
you can never subtract inequalities. you can only add them.

- 1 < 0
-2 < 0
If you add both inequalities you get -3 < 0, which is correct.

If you subtract 2nd statement from 1 i.e.

-1 < 0
-2 < 0
- -
-------

1 < 0 - incorrect

chipbmk wrote:
Why can we not do this for statement 1:

Given: W+X<0

Statement 1: X+Y<0

Given --> X+W<0
Statement 1--> X+Y<0
______ (subtract the statements)
= W-Y<0 or W
Doesnt that give you a definitive "no" to the question is w-y>0? or is w>y? appears like it does to me ... let me know

missrochelle Master | Next Rank: 500 Posts
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Sun Aug 29, 2010 4:22 pm
mehravikas wrote:
you can never subtract inequalities. you can only add them.

- 1 < 0
-2 < 0
If you add both inequalities you get -3 < 0, which is correct.

If you subtract 2nd statement from 1 i.e.

-1 < 0
-2 < 0
- -
-------

1 < 0 - incorrect
[/quote]IF YOU ADD THE INEQUALITY IN STATEMENT 1, TO THE STEM THEN HOW DO YOU GET -3 <1?

W + X < 0
X+ Y < 0
W+2X+Y < 0
WHICH DOESN'T ALLOW YOU TO ISOLATE W-Y..... IS THIS INCORRECT?

andy123 Senior | Next Rank: 100 Posts
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Sun Mar 13, 2011 9:32 am
W + X < 0
W < -X or W > X,

Is it OK to convert:

W < -X --- >> to ---- >> W > X,

I thought if we multiply by -1 , then we have to multiply both the sides of the equations and reverse the inequality ??

so in thi case: W < -X should not it be converted to -W > X ???

HSPA Legendary Member
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Mon Mar 14, 2011 2:57 am
w-y = w+x-x-y = (w+x)-(x+y)

Now let us use A (x+y <0) : (w+x)-(x+y) = -ve - ( -ve) [INSUFFICIENT]... we dont know how much negitive each fellow is
Now let us use B :
Consider w = 1, x = -2, y = -3
then (W+X)-(X+Y) = -1+5
w= 100, x = -101 then y is more negitive

But now
w= -1, x=0 so w+x <0 then x>y so y = -1... no w>y so y = -2...

Hello All ..... B seems fine for me

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Mon Mar 14, 2011 3:35 am
Perhaps I got lost in inequality translations, after plug in and with condition given (w+x<0) I figured |x| could not be more than |w| - so B is Sufficient.
thanks

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ankur.agrawal Master | Next Rank: 500 Posts
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Mon Mar 14, 2011 7:13 am
[quote="mmgmat2008"](1) x+y <0

W+x<0 ; W-y>0 or is W>y ?

1) Take w =-2 & x=-3 y=-4 ; These value satisfies W+x<0 & x+y <0

Is W>y. From Values taken it seems Yes it is.

Lets test another set of values : x=1 ; y=-2 ; w=-3

Is W>y . No . A yes & a No . This Statement is not sufficient.

2) Taking the same value for the first case as above:

Take w =-2 & x=-3 y=-4. These values satisfies y
Is w> y . Yes . Lets check another set of values.

w=2 ; x=-3 ; y=-4. again a yes.

If we use this method i think the answer should be D. lets check algebraically for the 2nd Statement.

W+x <0 ; y
Ist Case : Both Negative : Yes W>y
2nd Case: W + & x - (x has to be more negative than w is positive) = Yes W>y
3rd Case : W- & x+ ( W has to be more negative than x is +)= Yes W>y.

Am i missing sumthing.

I Think B

ankur.agrawal Master | Next Rank: 500 Posts
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Mon Mar 14, 2011 7:15 am
[quote="mmgmat2008"](1) x+y <0

W+x<0 ; W-y>0 or is W>y ?

1) Take w =-2 & x=-3 y=-4 ; These value satisfies W+x<0 & x+y <0

Is W>y. From Values taken it seems Yes it is.

Lets test another set of values : x=1 ; y=-2 ; w=-3

Is W>y . No . A yes & a No . This Statement is not sufficient.

2) Taking the same value for the first case as above:

Take w =-2 & x=-3 y=-4. These values satisfies y
Is w> y . Yes . Lets check another set of values.

w=2 ; x=-3 ; y=-4. again a yes.

If we use this method i think the answer should be D. lets check algebraically for the 2nd Statement.

W+x <0 ; y
Ist Case : Both Negative : Yes W>y
2nd Case: W + & x - (x has to be more negative than w is positive) = Yes W>y
3rd Case : W- & x+ ( W has to be more negative than x is +)= Yes W>y.

Am i missing sumthing.

I Think B

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