I think the crux of the problem is managing the time and not really the solution part of it. I am sure most ppl here would arrive at the answer (which is A btw). But hats off to you Brent, a very nice solution indeed.Brent@GMATPrepNow wrote:Nice work, Logitech
My solution is below. Note that we don�t need to consider Ann�s portion in the solution. We can just let K be the money remaining after Ann has received her portion and go from there.
Our equation will use the fact that, once we remove Bob�s portion, we have $32 for Chloe.
So, we get K � Bob�s $ = 32
The equation is K-4 � (K-4)/3 = 32
Solve for K (K=52) and then determine Bob�s portion ($20).
The answer is, indeed, A
Unfortunately, I went the conventional route: Anyways, here is what I did:
Let total money be x. (i have omitted several steps)
Amount Anna got: (x+4)/2
Amount Bob got: (x+12)/6
Equate that to amount received by C and you get x= 108.
Therefore Bob got $20.