Hi,
Answer is A. $20.
My approach is: A receives 4 +x/2. where let x be remaining amount.
after A receives the amount, remaining amount would be x/2.
Bob will receive now 4+1/3*(x/2)=4+x/6.
after deducting bob's amount leftover is given to C.
hence $32= x-{x/2+x/6}=x/3
thus x=$96
Therefore Bob receives=$4+$96/6=4+16=$20.
5-Day Free Trial
5-day free, full-access trial TTP
Available with Beat the GMAT members only code
MORE DETAILS
Tough word problem - dividing $
-
[email protected]
- Newbie | Next Rank: 10 Posts
- Posts: 1
- Joined: Mon Jan 03, 2011 1:53 am
-
krishnakumar.ks
- Senior | Next Rank: 100 Posts
- Posts: 65
- Joined: Mon Apr 04, 2011 6:22 am
- Thanked: 4 times
Great approach. It really helps. Thanks BrentBrent@GMATPrepNow wrote:Nice work, Logitech
My solution is below. Note that we don�t need to consider Ann�s portion in the solution. We can just let K be the money remaining after Ann has received her portion and go from there.
Our equation will use the fact that, once we remove Bob�s portion, we have $32 for Chloe.
So, we get K � Bob�s $ = 32
The equation is K-4 � (K-4)/3 = 32
Solve for K (K=52) and then determine Bob�s portion ($20).
The answer is, indeed, A
-
v_eshwar
- Newbie | Next Rank: 10 Posts
- Posts: 1
- Joined: Mon Jun 22, 2009 11:49 am
- Location: Columbus, Ohio, USA
Thank you 
Brent@GMATPrepNow wrote:Nice work, Logitech
My solution is below. Note that we don�t need to consider Ann�s portion in the solution. We can just let K be the money remaining after Ann has received her portion and go from there.
Our equation will use the fact that, once we remove Bob�s portion, we have $32 for Chloe.
So, we get K � Bob�s $ = 32
The equation is K-4 � (K-4)/3 = 32
Solve for K (K=52) and then determine Bob�s portion ($20).
The answer is, indeed, A
-
dv2020
- Master | Next Rank: 500 Posts
- Posts: 112
- Joined: Sun Nov 08, 2009 9:39 pm
- Location: Delhi
- Thanked: 2 times
That's brilliant indeed
I am solving algebraically somehow unable to solve it.....
I am solving algebraically somehow unable to solve it.....
kamu wrote:Bob took $4 + 1/3 of leftover..
that implies 2/3rds is left for Chloe..
if 2/3 of leftover = $32
1/3 of leftover = $16
$16+$4 = $20.
Hi everyone..
I din't quite get this one..
kamu wrote:
Bob took $4 + 1/3 of leftover..
that implies 2/3rds is left for Chloe.. ( Shudn't it be 2/3rd - 4 is left for Chole ?? )
if 2/3 of leftover = $32
1/3 of leftover = $16
$16+$4 = $20.
I din't quite get this one..
kamu wrote:
Bob took $4 + 1/3 of leftover..
that implies 2/3rds is left for Chloe.. ( Shudn't it be 2/3rd - 4 is left for Chole ?? )
if 2/3 of leftover = $32
1/3 of leftover = $16
$16+$4 = $20.
-
Warlock007
- Senior | Next Rank: 100 Posts
- Posts: 41
- Joined: Sat Jan 08, 2011 7:34 am
- Thanked: 2 times
- Followed by:1 members
Thats cool explainationBrent@GMATPrepNow wrote:Nice work, Logitech
My solution is below. Note that we don�t need to consider Ann�s portion in the solution. We can just let K be the money remaining after Ann has received her portion and go from there.
Our equation will use the fact that, once we remove Bob�s portion, we have $32 for Chloe.
So, we get K � Bob�s $ = 32
The equation is K-4 � (K-4)/3 = 32
Solve for K (K=52) and then determine Bob�s portion ($20).
The answer is, indeed, A
couldn't even think this can be this much simple.......
-
Keerthibme
- Newbie | Next Rank: 10 Posts
- Posts: 1
- Joined: Sun Apr 03, 2011 11:28 pm
- Thanked: 1 times
Please let me know where I went wrong
let total amount = x
Ann's share = 4+(x-4)/2
amount remaining now = x-ann's share = x-4-(x-4)/2= x/2-2=(x-4)/2
Bob's share = 4+1/3((x-4)/2)=4+(x-4)/6
chole's share = 32
Sum of Ann's, Bob's and chole's share is total amount
32+4+(x-4)/2+4+(x-4)/6 = x
This gives me x (total amount) as 112 and hence bob's share as 22.
Its quite long but still I am not getting how x-12/2 is obtained in the previous posts and same is asked by few other participants.
Regards,
Keerthi
let total amount = x
Ann's share = 4+(x-4)/2
amount remaining now = x-ann's share = x-4-(x-4)/2= x/2-2=(x-4)/2
Bob's share = 4+1/3((x-4)/2)=4+(x-4)/6
chole's share = 32
Sum of Ann's, Bob's and chole's share is total amount
32+4+(x-4)/2+4+(x-4)/6 = x
This gives me x (total amount) as 112 and hence bob's share as 22.
Its quite long but still I am not getting how x-12/2 is obtained in the previous posts and same is asked by few other participants.
Regards,
Keerthi
-
smackmartine
- Legendary Member
- Posts: 516
- Joined: Fri Jul 31, 2009 3:22 pm
- Thanked: 112 times
- Followed by:13 members
I also did some kinda back solving :
As Bob had $4+1/3 of Remaining--------> Chole was left with 2/3 of Remaining = 32
=> Remaining =(3/2)*32 = 48
Now, Bob's share = 4+ 1/3 of 48 = 4+16=20 (A)
As Bob had $4+1/3 of Remaining--------> Chole was left with 2/3 of Remaining = 32
=> Remaining =(3/2)*32 = 48
Now, Bob's share = 4+ 1/3 of 48 = 4+16=20 (A)
-
worldpeace93
- Junior | Next Rank: 30 Posts
- Posts: 21
- Joined: Sun Jun 05, 2011 10:39 pm
- Thanked: 2 times
- Followed by:1 members
-
Warlock007
- Senior | Next Rank: 100 Posts
- Posts: 41
- Joined: Sat Jan 08, 2011 7:34 am
- Thanked: 2 times
- Followed by:1 members
Here is my simplest magical solutionBrent@GMATPrepNow wrote:A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money did Bob receive?
A) 20
B) 22
C) 24
D) 26
E) 52
Bob receives $4 plus one-third of what remains.
Finally, Chloe receives the remaining $32
since bob receives $4 + 1/3 (what remains =suppose it is 'R')
then 32 should be equal to the 2/3rd of the sum 'R'
now R => 2/3(R)=32 so R = 48 and 1/3rd of R is =16
so BOB receives 4+16=20 $
A is the answer
hope it helps
GMAT/MBA Expert
-
Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
I received a message asking me to explain how Logitech arrived at the following amount for Bob: 4 + 1/3 [(X-12)/2]Brent@GMATPrepNow wrote:A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money did Bob receive?
A) 20
B) 22
C) 24
D) 26
E) 52
To do this, let's first simplify the amount that Logitech says Ann received.
If we let x = the original sum of money, then Ann receives 4 + (x-4)/2
To simplify this, we can rewrite this as 8/2 + (x-4)/2 which equals (8+x-4)/2 = (x+4)/2
So, Ann received (x+4)/2
Bob receives $4 plus 1/3 of what remains.
Well, what remains?
We began with x dollars and gave (x+4)/2 to Ann, which leaves x - (x+4)/2
Also, we just gave Bob $4, which leaves x - (x+4)/2 - 4
Bob gets 1/3 of x - (x+4)/2 - 4
To simplify x -(x+4)/2 - 4, we can rewrite it as 2x/2 - (x+4)/2 - 8/2
This equals (2x-x-4-8)/2 = (x-12)/2
So, Bob gets 4 plus 1/3 of (x-12)/2
In other words, Bob gets 4 + 1/3[(x-12)/2]
Of course, we've now seen a faster solution. But Logitech's method works too.
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
-
winniethepooh
- Master | Next Rank: 500 Posts
- Posts: 370
- Joined: Sat Jun 11, 2011 8:50 pm
- Location: Arlington, MA.
- Thanked: 27 times
- Followed by:2 members
Hey Brent,
Thanks for the reply, you've been really helpful!
Does this mean that I am wrong if I say:
Bob's share = 4 + x-{[x+4/2]-4}* 1/3 ??
I am talking about the placement of brackets.
Thanks for the reply, you've been really helpful!
Does this mean that I am wrong if I say:
Bob's share = 4 + x-{[x+4/2]-4}* 1/3 ??
I am talking about the placement of brackets.
