1/3 is non terminating.
1/2 and 1/5 are terminating fraction,
so, b and d will decides terminating of p/q
if b > d then p/q will be terminating decimal.
if b < d then p/q will be non terminating decimal.

Hence, st 1 is not sufficient as discussed above.
st2 is sufficient

Hence B

statement 1. a = b -1 ==> a[(a+1)^2] = (b -1)(b)^2 It depends on value of a or b so, st1 is not sufficient. Statement2. a = (b^2) - 1 ==> a(b)^2 = a(a +1) = ((b)^2 + 1)((b)^2) Again it depends on value of a or b so, st2 is also not sufficient. consider both together. a = b - 1 --- (1) a = b^2 -1 = (...

Ans C
Basically you have to arrange 4 Y(to rain) and 3N (not to rain)
= 7!/(4!*3!) = 35

Hence prob = 35/2^7 = 35/128

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