Search found 107 matches
You are right Vemuri. I was not careful. It should be 119. I'll edit on my posting and not to mislead people.
Thanks!
- by pakaskwa
Sun Apr 26, 2009 11:13 pm- Forum: Problem Solving
- Topic: How Many 2 Elemen Subsets of.....
- Replies: 6
- Views: 1692
1st, we need to determine if it's a "combination" or "permutation" question. In the question stem, it says "pair of elements 7 and 9". A pair means "7,9" and "9,7" are the same. So it's a combination issue. The order of 7 and 9 doesn't matter. 2nd, i...
- by pakaskwa
Sat Apr 25, 2009 2:43 pm- Forum: Problem Solving
- Topic: How Many 2 Elemen Subsets of.....
- Replies: 6
- Views: 1692
IMO, A. Stmt 1 AD=AC --> angle ADC=ACD --> angle ADE=ACB and we know that angle EAD=BAC --> AED=ABC So AB=AE. Stmt 1 SUFF. Stmt 2 Let angle EAD=DAC=CAB=x Since AC=CB --> angle ABC=CAB=x --> angle ACB=180-ABC-CAB=180-2x --> angle ACD=180-ACB=180-(180-2x)=2x --> angle ADC=180-3x --> angle ADE=3x --> a...
- by pakaskwa
Sat Apr 25, 2009 2:28 pm- Forum: Data Sufficiency
- Topic: angles and sides...
- Replies: 2
- Views: 1150
IMO it's B.
To pick out any 2 items out of 3 items, there are 2C3 possible ways.
To pick out 2 selected items out of 3 items, there are 2C2 possible ways.
Therefore, to pick out any 2 items out of 3 items, but NOT including those 2 selected items are:
2C3-2C2=3-1=2
- by pakaskwa
Sat Apr 25, 2009 2:06 pm- Forum: Problem Solving
- Topic: How Many 2 Elemen Subsets of.....
- Replies: 6
- Views: 1692
a) There's only 1 first prize in 30 tickets. If the boy has 1 ticket, his probability is 1/30. When he has 3 tickets, it's 3*1/30=1/10. b) To win first prize, his probability is 1/10; to win 2nd prize, probability is 2/29 (29 tickets left). To win both, probability is 1/10*2/29=1/145 c) The probabil...
- by pakaskwa
Sat Apr 25, 2009 1:51 pm- Forum: Problem Solving
- Topic: raffle: probability
- Replies: 4
- Views: 5647
IMO, E. It's a bit tricky to understand "divided successively". IMO, it means that, number x is divided by 4 first, quotient is n, remainder is 1. Then n is divided by 5, quotient is m, remainder is 4. (m and n are positive ingeters.) If my understanding is correct, number x = (5m+4)4n+1 =...
- by pakaskwa
Tue Apr 21, 2009 12:02 pm- Forum: Problem Solving
- Topic: successive division
- Replies: 3
- Views: 14412
IMO choice E. Let x be the number, we can get x=31n+29. Since 31 is an odd number, 31n could be odd or even (it's odd when n is odd, it's even when n is even). So 31n+29 can be either odd or even. We can easily deduct: when odd numbers are divided by even number 16, there must be remainders; when ev...
- by pakaskwa
Tue Apr 21, 2009 11:38 am- Forum: Problem Solving
- Topic: confused divisor
- Replies: 2
- Views: 1295
Stmt 2:
If you draw a line, and arrange point A, B, and C in following sequence:
1. A-C-B, distance AC is 5, distance BC is 20. (distance AB is 25) C is between A and B.
2. C-A-B, AC is 5, BC is 20. (but AB is 15). C is NOT between A and B.
So stmt 2 is not sufficient.
- by pakaskwa
Tue Apr 21, 2009 11:27 am- Forum: Problem Solving
- Topic: Point A lies to the left of point B
- Replies: 1
- Views: 987
Personally I dont' think any GMAT materials are close enough to real test, including Princeton, MCGMAT, Manhatten, Kaplan, etc. And trust me I tried quite a few of them. The best materials out there is OG. Get your hands on all OGs, like OG10-12. Math: most of the math books are relatively easier th...
- by pakaskwa
Tue Apr 21, 2009 11:15 am- Forum: GMAT Strategy
- Topic: What to do? Gmat Soon
- Replies: 2
- Views: 1350
From question stem we can get:
g(2)=(2^2+2)/(2-1)=6 --> 1/g(2)=1/6
g(x)=(x^2+2)/(x-1) --> 1/g(x)=(x-1) /(x^2+2)
[1/g(2)]*[1/g(x)] = (x-1) /6(x^2+2)
Choose D.
- by pakaskwa
Tue Apr 21, 2009 10:49 am- Forum: Problem Solving
- Topic: GMATPrep function
- Replies: 1
- Views: 1094
You are right CR. I made a mistake with Stmt 2. From stmt 2, we can get x(x+1)(x-1)<0 Then there are 3 possiblities: 1. x>0, x+1>0, x-1<0 --> 0<x<1 2. x>0, x+1<0, x-1>0 --> x>1 (out) 3. x<0, x+1>0, x-1>0 --> no solution So from stmt 2 we know that x>0. SUFF! Choice is D! I'll edit on my previous pos...
- by pakaskwa
Thu Apr 16, 2009 3:02 pm- Forum: Data Sufficiency
- Topic: Is X>0?
- Replies: 20
- Views: 3669
Hi CR and all, Thanks for your help. It's trickier than it looks eh? CR, my approach is similar to yours, yet I got different answer. From stmt 1 , we can get x(x-1)<0 so there are two solutions: 1. x<0, x>1, or 2. x>0, x<1 --> 0<x<1 The question stem told us that -1<x<1, so 1st solution is out. 2nd...
- by pakaskwa
Thu Apr 16, 2009 1:24 pm- Forum: Data Sufficiency
- Topic: Is X>0?
- Replies: 20
- Views: 3669
- by pakaskwa
Wed Apr 15, 2009 2:29 pm- Forum: Data Sufficiency
- Topic: GMAT Prep Prac 1 - Q19
- Replies: 15
- Views: 7764
Is X>0?
If -1<x<1, is x>0?
(1) x^2<x
(2) x^3<x
A friend of mine asked me this question, and we don't know the OA.
- by pakaskwa
Wed Apr 15, 2009 2:20 pm- Forum: Data Sufficiency
- Topic: Is X>0?
- Replies: 20
- Views: 3669
I went for E too. I thought "its" is ambiguous pronoun here.
I understand the tense needed here is present perfect. But I can't tell which error is more serious in the eyes of GMAC... Or maybe "its" here is not an error since it can only refer to P.R. China?
- by pakaskwa
Sun Apr 12, 2009 2:06 pm- Forum: Sentence Correction
- Topic: 1000sc# 283
- Replies: 9
- Views: 9327