If the circle above has a radius of 4, what is the perimeter of the inscribed equilateral triangle?
(other details in the picture attached)
PS - Triangle
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Think the centre of the circle and connect it to the vertex of the triangle. This is equal to 4. Thus three line to the vertax of the triangle are equal making the triangle keeping two sides equal. Also, any angle on the diameter of the semicircle equals to 90 degreee. This becomes a right angled triangle. Thus the hypotneuse becomes 4 root 2.
It applies to all 3 Hypotneuse. Sum up and we get 12 root 2.
I know my explanation is little rusty, but logically it should suffice.
It applies to all 3 Hypotneuse. Sum up and we get 12 root 2.
I know my explanation is little rusty, but logically it should suffice.
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Alright to make things easy I have attached a diagram and will try to solve the problem using different appraoches!
i.e. CO/OD = 2/1
4/OD = 2/1 (CO = radius of the circle = 4 units)
OD = 2 units.
Let the length of the side of the equilateral triangle be X, then In right angled triangle CDA,
AC = X, AD = 0.5X(CD is a perpendicular bisector) and CD = 6. Applying Pythagorean Theorem,
X^2 = (0.5X)^2 + 6^2
(3/4)*X^2 = 36.
X = 4 * square root(3)
Perimeter = 3X = 12*Square root(3)
pi * R^2 = pi * (X^2) / 3
4^2 = (X^2) / 3
X = 4 * square root(3)
Perimeter = 3X = 12 * Square root(3)
OA/Sin(OBA) = AB/Sin(AOB)
4/Sin 30 = AB/Sin 120
4/(1/2) = AB/((Square root(3))/2)
AB = 4 * square root(3)
Perimeter = 3X = 12 * Square root(3)
Cos 30 = AD/AO = Square root(3)/2 = (AB/2)/AO (AO = 4)
AB = 4 * square root(3)
Perimeter = 3X = 12 * Square root(3)
Since the triangle is an equilateral triangle we know that the measure of the interior angle is 60 degrees. Join the centre(O here) to the corners of the triangle ABC. The center of the circle acts as a centroid and the line segment AD median/perpendicular bisector. The centroid divides each median in a ratio of 2:1.Approach A:
i.e. CO/OD = 2/1
4/OD = 2/1 (CO = radius of the circle = 4 units)
OD = 2 units.
Let the length of the side of the equilateral triangle be X, then In right angled triangle CDA,
AC = X, AD = 0.5X(CD is a perpendicular bisector) and CD = 6. Applying Pythagorean Theorem,
X^2 = (0.5X)^2 + 6^2
(3/4)*X^2 = 36.
X = 4 * square root(3)
Perimeter = 3X = 12*Square root(3)
If an equilateral triangle of side 'X' is inscribed inside a circle, then area of circle = pi (X^2) / 3. We know that the area of the circle = pi * R^2 (Where R = Radius of the circle)Approach B:
pi * R^2 = pi * (X^2) / 3
4^2 = (X^2) / 3
X = 4 * square root(3)
Perimeter = 3X = 12 * Square root(3)
In triangle OAB, Applying sine ruleApproach C:
OA/Sin(OBA) = AB/Sin(AOB)
4/Sin 30 = AB/Sin 120
4/(1/2) = AB/((Square root(3))/2)
AB = 4 * square root(3)
Perimeter = 3X = 12 * Square root(3)
In Triangle ODA,Approach D:
Cos 30 = AD/AO = Square root(3)/2 = (AB/2)/AO (AO = 4)
AB = 4 * square root(3)
Perimeter = 3X = 12 * Square root(3)
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Triangle OAB is 30-60-90 triangle.
Since AB = 2√3, so each side of the equilateral triangle = 4√3
Hence, perimeter of the equilateral triangle = 3 * (4√3) = 12√3
The correct answer is D.
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What is the perimeter of the inscribed equilateral triangle?
Answer choices: 6√2, 6√3, 12√2, 12√3, 24.
Each side of the triangle ≈ 6.
Perimeter ≈ 18.
Eliminate A and B, which are way too small, and E, which is too big.
The correct answer must be C or D.
√2 implies a 45-45-90 triangle; √3 implies a 30-60-90 triangle.
Since each angle of the equilateral triangle = 60, √2 makes no sense here.
Eliminate C.
The correct answer is D.
Always look for opportunities to ballpark.
Always look at the answer choices.
The approach above requires little insight and allows us to determine the correct answer in mere seconds.
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- karthikpandian19
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Gunjan,
See the correct answer below.
See the correct answer below.
gunjan1208 wrote:Think the centre of the circle and connect it to the vertex of the triangle. This is equal to 4. Thus three line to the vertax of the triangle are equal making the triangle keeping two sides equal. Also, any angle on the diameter of the semicircle equals to 90 degreee. This becomes a right angled triangle. Thus the hypotneuse becomes 4 root 2.
It applies to all 3 Hypotneuse. Sum up and we get 12 root 2.
I know my explanation is little rusty, but logically it should suffice.
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Hi Karthik,
Thanks. Actually I realized later that the second tule what I applied for finding the hypotenuse was not right. I am good with this.
Thank you very much again.
Thanks. Actually I realized later that the second tule what I applied for finding the hypotenuse was not right. I am good with this.
Thank you very much again.
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HelloGMATGuruNY wrote:
What is the perimeter of the inscribed equilateral triangle?
Answer choices: 6√2, 6√3, 12√2, 12√3, 24.
Each side of the triangle ≈ 6.
Perimeter ≈ 18.
Eliminate A and B, which are way too small, and E, which is too big.
The correct answer must be C or D.
√2 implies a 45-45-90 triangle; √3 implies a 30-60-90 triangle.
Since each angle of the equilateral triangle = 60, √2 makes no sense here.
Eliminate C.
The correct answer is D.
Always look for opportunities to ballpark.
Always look at the answer choices.
The approach above requires little insight and allows us to determine the correct answer in mere seconds.
Sorry i dint understand two points here
*I am missing something. Please confirm how do we reach - Each side of the triangle ≈ 6?
*√2 implies a 45-45-90 triangle; √3 implies a 30-60-90 triangle.
Since each angle of the equilateral triangle = 60, √2 makes no sense here.
I believe we are not drawing to scale since visually i cannot see any 30-60-90 in the triangle. It appears more like 45-45-90 triangle after drawing radius.
thanks.
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The drawing shows 3 congruent triangles, each with two sides of 4 forming a 120 degree angle.melguy wrote:HelloGMATGuruNY wrote:
What is the perimeter of the inscribed equilateral triangle?
Answer choices: 6√2, 6√3, 12√2, 12√3, 24.
Each side of the triangle ≈ 6.
Perimeter ≈ 18.
Eliminate A and B, which are way too small, and E, which is too big.
The correct answer must be C or D.
√2 implies a 45-45-90 triangle; √3 implies a 30-60-90 triangle.
Since each angle of the equilateral triangle = 60, √2 makes no sense here.
Eliminate C.
The correct answer is D.
Always look for opportunities to ballpark.
Always look at the answer choices.
The approach above requires little insight and allows us to determine the correct answer in mere seconds.
Sorry i dint understand two points here
*I am missing something. Please confirm how do we reach - Each side of the triangle ≈ 6?
The third side of each triangle must be less than 8, since the third side of a triangle must be less than the sum of the other 2 sides.
Since the triangles are not equilateral, the third side of each triangle must be greater than 4.
Splitting the difference between 8 and 4, I estimated that the third side of each triangle ≈ 6.
An equilateral triangle can easily be divided into 30-60-90 triangles:*√2 implies a 45-45-90 triangle; √3 implies a 30-60-90 triangle.
Since each angle of the equilateral triangle = 60, √2 makes no sense here.
I believe we are not drawing to scale since visually i cannot see any 30-60-90 in the triangle. It appears more like 45-45-90 triangle after drawing radius.
thanks.
Equilateral triangles and 30-60-90 triangles are common bedfellows.
Equilateral triangles and 45-45-90 triangles are not.
There is almost no chance that the perimeter of an equilateral triangle on the GMAT will involve √2, which is associated with a 45-45-90 triangle.
Last edited by GMATGuruNY on Wed Dec 07, 2011 6:45 am, edited 1 time in total.
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Hi. I dont understand why it is not 12√2? we have three 45:45:90 triangles with two legs of 4. So the hypotenuse is 4√2. The perimeter will be 3(4√2)Equilateral triangles and 30-60-90 triangles are common bedfellows.
Equilateral triangles and 45-45-90 triangles are not.
There is almost no chance that the perimeter of an equilateral triangle on the GMAT will involve √2, which is associated with a 45-45-90 triangle.
What am I missing here?
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Hi Zoser,
The three triangles you are referring to are NOT 45/45/90s - they're 30/30/120s. If you read the other explanations in this thread, you'll see how a 30/30/120 can be broken down into two 30/60/90s (back-to-back) - and how you can calculate the length of a side of the equilateral triangle.
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The three triangles you are referring to are NOT 45/45/90s - they're 30/30/120s. If you read the other explanations in this thread, you'll see how a 30/30/120 can be broken down into two 30/60/90s (back-to-back) - and how you can calculate the length of a side of the equilateral triangle.
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Inspired from Mitch's analysis...
We see that the circumference of the circle = 2*pi*4 = 8*3.14 = ~25.
Thus, the perimeter of the inscribed equilateral triangle must be less than 25.
We find that option E: 24 is too close to 25, thus it cannot be an answer. Similarly, option A: 6√2 and option B: 6√3 are too small. The answer would be one between option C: 12√2 and option D: 12√3.
As Mitch argued beautifully that since √2 implies a 45-45-90 triangle; √3 implies a 30-60-90 triangle.
Since each angle of the equilateral triangle = 60, √2 makes no sense here. So option C cannot be correct.
The correct answer: D
Hope this helps!
Relevant book: Manhattan Review GMAT Geometry Guide
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