The ratio Women / Children is 5/2 and we are looking for the number of men on the tour.hpgmat wrote:on a certain sight seeing tour, ratio of number of women to children was 5 to 2. what was the unmber of men on the sight seeing tour?
1) ratio of nmber of children to men was 5 to 11
2) the number of women was less than 30
Not sure I get the W:C:M part and the combined one too.palvarez wrote:1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff
Combined, sufficient: W = 25
M = 22
HE HAS MULTIPLIED FIRST RATIO BY 2 AND THE SECOND RATIO BY 5carllecat wrote:Not sure I get the W:C:M part and the combined one too.palvarez wrote:1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff
Combined, sufficient: W = 25
M = 22
hpgmat wrote:HE HAS MULTIPLIED FIRST RATIO BY 2 AND THE SECOND RATIO BY 5carllecat wrote:Not sure I get the W:C:M part and the combined one too.palvarez wrote:1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff
Combined, sufficient: W = 25
M = 22
WE GET C:M EQUAL TO 10:22
AND W:C EQUAL TO 25:10
NOW WE COMBINE BOTH RATIOS ( 10 IS COMMON)
YES THAT PUTS A CONSTRAINT ON IT IF W > 30 ANND LETS ASSUME IF IT WAS 50 THEN NUMBER OF MEN WOULD BE 44 OR IF IT WAS 100 , THEN NUMBER OF MEN WOULD BE 88. KNOWING W < 30 THERE IS ONLY ONE CONDITION WHICH SATISFIES THE RATIO SINCE WE CAN NOT HAVE FRACTIONS AS NUMBER OF PEOPLE ( ONLY INTEGERS COUNT NUMBER OF PEOPLE)carllecat wrote:hpgmat wrote:HE HAS MULTIPLIED FIRST RATIO BY 2 AND THE SECOND RATIO BY 5carllecat wrote:Not sure I get the W:C:M part and the combined one too.palvarez wrote:1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff
Combined, sufficient: W = 25
M = 22
WE GET C:M EQUAL TO 10:22
AND W:C EQUAL TO 25:10
NOW WE COMBINE BOTH RATIOS ( 10 IS COMMON)
Then why is the answer C and not A? Does it really matter that W < 30?
