1) If (1/5)m(1/4)18 = 1/2(10)35, m?
a. 18
b. 17
c. 21
d. 35
e. 3
is that equation 1/5 x m x 1/4 x 18 = 1/2 x 10 x 35? because it doesn't equal any of those answers. if you're trying to do square roots use x^2 to show x square
2) (-1)k+1(½k). T is the sum of the first 10 k, is t
a. > 2
b. between 1 and 2
c. between ½ and 1
d. between ¼ and ½
e. < ¼
Really Stuck on these...
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Talkativetree
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Correction to Okigbo's post:
The first question should read (1/5)^(m)*(1/4)^(18)=1/(2*10^35)
It can be solved in the following manner:
1/5^m*1/(2^2)^(18)=1/2*5^35*2^35
1/5^m*1/2^(36)=1/2^36*5^35
Compare both sides to get m=35.
The first question should read (1/5)^(m)*(1/4)^(18)=1/(2*10^35)
It can be solved in the following manner:
1/5^m*1/(2^2)^(18)=1/2*5^35*2^35
1/5^m*1/2^(36)=1/2^36*5^35
Compare both sides to get m=35.
