if (y+3)(y-1) -(y-2)(y-1)=r(y-1) what is value of y?
1) r^2=25
2) r=5
The[spoiler] OA=E[/spoiler]. I got to OA also. but i have different approach of solving
let given eqn be solved to (y-1)(y+3 -y+2 -r)=0
=> (y-1)(5-r)=0
it says y=1..
so there is no need for any of the statement. Answer should be D
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(y+3)(y-1) -(y-2)(y-1)=r(y-1)
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tohellandback
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it does not say y=1shargaur wrote:if (y+3)(y-1) -(y-2)(y-1)=r(y-1) what is value of y?
1) r^2=25
2) r=5
The[spoiler] OA=E[/spoiler]. I got to OA also. but i have different approach of solving
let given eqn be solved to (y-1)(y+3 -y+2 -r)=0
=> (y-1)(5-r)=0
it says y=1..
so there is no need for any of the statement. Answer should be D
it says:
either, Y=1 OR r=5 OR both
1)r=5 or -5
if r=5, Y=any value is possible
NOT SUFF
2)same as 1
combined same as above
so E
The powers of two are bloody impolite!!
