What number times (1�3)^2 will give the value of 3^3?
A. 3
B. 9
C. 27
D. 108
E. 243
The OA is E.
Is there a way to solve it without trying option by option? Experts, may you help me please?
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What number times (1�3)^2 will give the value of 3^3?
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Brent@GMATPrepNow
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In other words, we want to solve the equation [(1�3)²]k = 3³ for kVincen wrote:What number times (1�3)² will give the value of 3³?
A. 3
B. 9
C. 27
D. 108
E. 243
First notice that 1/3 = 3^(-1)
So, (1�3)² = [3^(-1)]² = 3^(-2) [after we apply the Power of a Power law]
We have: [3^(-2)]k = 3³
Divide both side by 3^(-2) to get: k = 3³/3^(-2)
Apply Quotient law to get: k = 3^5 = 243
Answer: E
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Brent
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Scott@TargetTestPrep
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We can create the following equation in which k = the number:Vincen wrote:What number times (1�3)^2 will give the value of 3^3?
A. 3
B. 9
C. 27
D. 108
E. 243
k(1/3)^2 = 3^3
k(1/9) = 27
k = 243
Answer: E
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