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by karthikpandian19 » Wed Jun 06, 2012 6:21 pm
That's the fastest way to do this problem. Awesome
November Rain wrote:Hi,
I have also come up with ans E

However i used a different approach.

B's rate is 1/15, and B worked for 5 days so he as done 5/15 or 1/3 of the job.

So B should get (1/3) of 720 which is 240. Considering that the question is asking for his average daily wage, then its 240/5, which is 48
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by eagleeye » Wed Jun 06, 2012 6:55 pm
Since we are asked only for the average rate of each, and the total money for the job is 720.

Average daily wage of B = (Total Amount Paid)/(No. of days for B to do the "full" job) = 720/15 = 48$.


As long as people are paid for their part of the work, they will always receive average daily rate = (Total amount for the job)/(no of days it takes to do the job). This would have been a little bit harder of a question if the total money paid to C was asked. (By the way, it is impossible to find Cs daily, rate since we do not know how much can he/she finish in a day).

Let me know if this helps :).
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by karthikpandian19 » Wed Jun 06, 2012 7:15 pm
This is the FASTEST way to do, i think

You are always one step ahead in thinking
eagleeye wrote:Since we are asked only for the average rate of each, and the total money for the job is 720.

Average daily wage of B = (Total Amount Paid)/(No. of days for B to do the "full" job) = 720/15 = 48$.


As long as people are paid for their part of the work, they will always receive average daily rate = (Total amount for the job)/(no of days it takes to do the job). This would have been a little bit harder of a question if the total money paid to C was asked. (By the way, it is impossible to find Cs daily, rate since we do not know how much can he/she finish in a day).

Let me know if this helps :).
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by ShreeCS » Fri Jun 29, 2012 4:42 am
I understand the answer.. I do not understand how to identity the part of work A & B individually did out the the 3/4th piece of work they did together. Can you someone please explain step-wise how do you find out the portion of work B individually has done? Appreciate it!
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by karthikpandian19 » Fri Jun 29, 2012 2:19 pm
Shree,

Here it is, the prompt says "A and B individually can finish the piece of work in 12 days and 15 days respectively." & we are concerned only with avg. daily wage of B, so concentrate on B only.
So, A's rate = 1/12; B's rate = 1/15

1. B's rate = 1/15 (which means 1/15th of the work done in 1 day)

2. So, for 5 days
1/15 *5
1/3

B has done 1/3 of the work.

3. Now total money paid for A,B,C is 720$ and we know how much work B has done (1/3rd), so
B receives a total of 720*(1/3) for working 5 days.
240$ for 5 days

4. Question asks for avg rate of B:
So, 240/5
answer is 48

Hope this helps
I understand the answer.. I do not understand how to identity the part of work A & B individually did out the the 3/4th piece of work they did together. Can you someone please explain step-wise how do you find out the portion of work B individually has done? Appreciate it!
sanju09 wrote:A, B, and C were to be paid in proportion to the part of work they did while working on the same piece of work. A and B individually can finish the piece of work in 12 days and 15 days respectively. They worked together for five days and then C completed the remaining work all alone. If $720 was the net sum to be paid for the entire work, what was the average daily wage of B?
(A) $144
(B) $90
(C) $60
(D) $54
(E) $48
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by ShreeCS » Fri Jun 29, 2012 2:47 pm
Thanks Karthik!! Appreciate it!!
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by shantanu86 » Fri Jun 29, 2012 7:17 pm
imo 48
If you feel like it, hit thanks :)
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by anujan007 » Thu Aug 02, 2012 5:16 pm
Good one...some fantastic explanations.

I reached out to B = 1/3 of the job and also the share being 240 but then got stuck. The mistake that I made was that I did not realize the average per day was asked. Takes me back to square one i.e. the question asked needs to be looked into closely.
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by sureshcpa » Fri Dec 14, 2012 7:08 am
Simple 2 step approach. No need to calculate 5 days total work or remaining work.

B's 1 day work = 1/15

Total amount for work = 720

Average (1 day work pay) = 720/15 = 48 (Ans: E)

Lots of information make this question complicated.
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by jaspreetsra » Tue Jan 13, 2015 1:26 am
A, B, and C were to be paid in proportion to the part of work they did while working on the same piece of work. A and B individually can finish the piece of work in 12 days and 15 days respectively. They worked together for five days and then C completed the remaining work all alone. If $720 was the net sum to be paid for the entire work, what was the average daily wage of B?

(A) $144
(B) $90
(C) $60
(D) $54
(E) $48

I don't know whether it is making sense or not. As B can finish work in 15 days and the total amt given for whole work is $ 720. We need avg. daily wage of B, so I just divided 720/15 = 48.

IMO: E

Help plz.
Can I do like this?
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by [email protected] » Tue Jan 13, 2015 11:34 am
Hi jaspreetsra,

There's a lot of information in this prompt that is NOT required to answer the question.

The question asks us for the average DAILY wage for B, so we'll focus on that worker.

We're told that B can complete a job in 15 days and that he works for 5 days. This means that he completed 5/15 = 1/3 of the job.

We're also told that workers are paid in PROPORTION to the work that they did. Person B did 1/3 of the job, so B gets 1/3 of the pay. Since the total pay was $720, person B gets 720/3 = $240

To get the average DAILY wage, we take the $240 paid and divide by the 5 days worked:

240/5 = $48/day

Final Answer: E

The fact that you can still get to the correct answer just by dividing 720 by 15 is a bit of coincidence (and dubious question design on the part of the writer).

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