Problem Solving

A and B traveled on the same road and at the same rate from Huntigdon to London. At the 50th Milestones from London, A overtook a drove of geese which were proceeding at the rate of 3miles in 2 hours; and two hours afterwards meet a waggon, which was moving at the rate of 9miles in 4hours. B overtook the same drove of geese at the 45th milestones and met the wagon exactly 40 minutes before he came to the 31st milestonnes. Where was B when A reached London?

25 miles from Huntigdon
45 miles from Huntigdon
25 miles from London
35 miles from London
45 miles from London

any taker for this one

maihuna wrote:A and B traveled on the same road and at the same rate

If they are traveling at the same rate, not sure why will they meet the geese at different times??

close approximation it is c. but I think something is wrong in the q

how I got it is very convuluted, so will try to explain
if A met geese at 50 stone and b met geese at 45 then geese travelled 5 miles at a speed of 1.5 m/h; so the time taken by geese is 3.3 hours, in other words b started 3.3 hours later than a.

now speed of van is 1.25 m/h so in 3.3 hours it travelled aprox 4 miles, so it means A wud hv met van at 35th stone.

so speed of A is (50-35)/2hrs = 7.5/hr.

so A is ahead of B by 3.3*7.5=25

however b travelled from 45 to 31 in 40 minutes so its speed is 21 m/h.

so not sure where it is going.

what is the OA. any expert