Musicat wrote:The arithmetic mean of the 5 consecutive integers starting with 's' is 'a'. What is the arithmetic mean of 9 consecutive integers that start with s + 2?
A 2 + s + a
B 22 + a
C 2s
D 2a + 2
E 4 + a
Consecutive integers constitute an EVENLY SPACED SET.
For any evenly spaced set, AVERAGE = MEDIAN.
The arithmetic mean of the 5 consecutive integers starting with 's' is 'a'.
Let s=1, implying that the 5 consecutive integers are as follows:
1, 2, 3, 4, 5.
Here, a = average = median = 3.
What is the arithmetic mean of 9 consecutive integers that start with s + 2?
Since s+2 = 1+2 = 3, the 9 consecutive integers starting with s+2 are as follows:
3, 4, 5, 6, 7, 8, 9, 10, 11.
Here, average = median = 7. This is our target.
Now plug s=1 and a=3 into the answers to see which yields our target value of 7.
Only
E works:
4 + a = 4 + 3 = 7.
The correct answer is
E.
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