If n is the smallest of three consecutive positive integers, which of the following must be true?
(A) n is divisible by 3
(B) n is even
(C) n is odd
(D) (n)(n + 2) is even
(E) n(n + 1)(n + 2) is divisible by 3
[spoiler]OA=E[/spoiler]
Source: Manhattan GMAT
If n is the smallest of three consecutive positive integers
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There's a nice rule says:VJesus12 wrote:If n is the smallest of three consecutive positive integers, which of the following must be true?
(A) n is divisible by 3
(B) n is even
(C) n is odd
(D) (n)(n + 2) is even
(E) n(n + 1)(n + 2) is divisible by 3
The product of k consecutive integers is divisible by k, k-1, k-2,...,2, and 1
So, for example, the product of any 5 consecutive integers will be divisible by 5, 4, 3, 2 and 1
Likewise, the product of any 11 consecutive integers will be divisible by 11, 10, 9, . . . 3, 2 and 1
By the above rule, the product of 3 consecutive integers will be divisible by 3, 2 and 1
If we recognize that n, n+1 and n+2 represent 3 consecutive integers
So, n(n + 1)(n + 2) must be divisible by 3
Answer: E
Cheers,
Brent
The product of 3 consecutive positive integers is divisible by 6
\(6=3*26=3∗2\), Thus the Product of \(3\) consecutive positive integers is divisible by both \(2\) and \(3\), Answer must be [spoiler](E)[/spoiler]
\(6=3*26=3∗2\), Thus the Product of \(3\) consecutive positive integers is divisible by both \(2\) and \(3\), Answer must be [spoiler](E)[/spoiler]
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Looking at the answer choices, we see that answer choice E represents the product of 3 consecutive integers, and that product is always divisible by 3! = 6, so it also must be divisible by 3.VJesus12 wrote:If n is the smallest of three consecutive positive integers, which of the following must be true?
(A) n is divisible by 3
(B) n is even
(C) n is odd
(D) (n)(n + 2) is even
(E) n(n + 1)(n + 2) is divisible by 3
[spoiler]OA=E[/spoiler]
Source: Manhattan GMAT
Answer: E
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